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Digiron [165]
2 years ago
11

Which of the following statement about the point (5,3 and ( 5,-3) is true?

Mathematics
2 answers:
Fantom [35]2 years ago
6 0

Answer:

A

Step-by-step explanation:

3241004551 [841]2 years ago
5 0

Answer:

I think it's A

Step-by-step explanation:

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Select the correct name for the following line.
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The correct name for the line shown is the answer choice C.

It can be A because the picture is a line not a ray and it cant be B because the picture shown is not a segment

Hope this helps :)
4 0
2 years ago
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Evaluate g/-5, when g=-5
daser333 [38]

Answer:

g/-5= 1

Step-by-step explanation:

g=-5, so -5/-5 is 1.

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3 years ago
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If a dog weighs 240 ounces, how many grams does the dog weigh?
agasfer [191]

Answer: If the dog weighed 240 ounces it would weigh 6803.89 grams

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3 years ago
Six students earned a perfect score on a history quiz. Only 5% of the entire grade earned a perfect score. How many students are
stiks02 [169]

Answer:

120

Step-by-step explanation:

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5 0
2 years ago
A particle moves so that its position vector with respect to the origin of a reference frame Oxyz is r(t)=bcos w t+bsin w t+vt k
sweet-ann [11.9K]

(i) Velocity is the rate of change of position, so if

<em>r</em><em>(t)</em> = <em>b</em> cos(<em>ω t </em>) <em>i</em> + <em>b</em> sin(<em>ω t </em>) <em>j</em> + <em>v</em> <em>t</em> <em>k</em>

then

<em>v</em><em>(t)</em> = d<em>r</em>/d<em>t</em>

<em>v</em><em>(t)</em> = -<em>b</em> <em>ω </em>sin(<em>ω t</em> ) <em>i</em> + <em>b</em> <em>ω</em> cos(<em>ω</em> <em>t</em> ) <em>j</em> + <em>v</em> <em>k</em>

The speed of the particle is the magnitude of the velocity, given by

|| <em>v</em><em>(t)</em> || = √[(-<em>b</em> <em>ω </em>sin(<em>ω t</em> ))² + (<em>b</em> <em>ω</em> cos(<em>ω</em> <em>t</em> ))² + <em>v</em> ²]

… = √[<em>b </em>²<em>ω </em>² + <em>v</em> ²]

(ii) The path is a helix. Suppose you zero out the <em>k</em> component. Then the path is a circle of radius <em>b</em>, and the value of <em>ω</em> determines how quickly a particle on the path traverses the circle. Now if you reintroduce the <em>k</em> component, the value of <em>v</em> will determine how far from the plane <em>z</em> = 0 the particle moves in a helical path as <em>t</em> varies.

(iii) Acceleration is the rate of change of velocity, so

<em>a</em><em>(t)</em> = d<em>v</em>/d<em>t</em>

<em>a</em><em>(t)</em> = -<em>b</em> <em>ω </em>²<em> </em>cos(<em>ω t</em> ) <em>i</em> - <em>b</em> <em>ω</em> ² sin(<em>ω</em> <em>t</em> ) <em>j</em>

3 0
3 years ago
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