Ask question

Ask question

All categories

3 years ago

11

Which of the following statement about the point (5,3 and ( 5,-3) is true?

2 answers:

Fantom [35]3 years ago

6 0

Answer:

A

Step-by-step explanation:

3241004551 [841]3 years ago

5 0

Answer:

I think it's A

Step-by-step explanation:

You might be interested in

Help agian plz if u do u will get points

igor_vitrenko [27]

The sales tax is 3.49 I think

3 0

3 years ago

Read 2 more answers

Can someone help me please

Lelechka [254]

Answer:

Step-by-step explanation:

6 0

3 years ago

A square and a circle intersect so that each side of the square contains a chord of the circle equal in length to the radius of

krek1111 [17]

Answer:

Step-by-step explanation:

it is given that Square contains a chord of of the circle equal to the radius thus from diagram

$QR=chord =radius =R$

If Chord is equal to radius then triangle PQR is an equilateral Triangle

Thus $QO=\frac{R}{2}=RO$

In triangle PQO applying Pythagoras theorem

$(PQ)^2=(PO)^2+(QO)^2$

$PO=\sqrt{(PQ)^2-(QO)^2}$

$PO=\sqrt{R^2-\frac{R^2}{4}}$

$PO=\frac{\sqrt{3}}{2}R$

Thus length of Side of square $=2PO=\sqrt{3}R$

Area of square $=(\sqrt{3}R)^2=3R^2$

Area of Circle $=\pi R^2$

Ratio of square to the circle $=\frac{3R^2}{\pi R^2}=\frac{3}{\pi }$

5 0

3 years ago

Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len

Rama09 [41]

The length of a curve <em>C</em> parameterized by a vector function <em>r</em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is

$\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt$

In this case, we have

<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> ) ==> d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )

<em>y(t)</em> = 5 - 2<em>t</em> ==> d<em>y</em>/d<em>t</em> = -2

and [<em>a</em>, <em>b</em>] = [0, 2]. The length of the curve is then

$\displaystyle\int_0^2 \sqrt{\left(e^t-e^{-t}\right)^2+(-2)^2} \,\mathrm dt = \int_0^2 \sqrt{e^{2t}-2+e^{-2t}+4}\,\mathrm dt$

$=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt$

$=\displaystyle\int_0^2\sqrt{\left(e^t+e^{-t}\right)^2} \,\mathrm dt$

$=\displaystyle\int_0^2\left(e^t+e^{-t}\right)\,\mathrm dt$

$=\left(e^t-e^{-t}\right)\bigg|_0^2 = \left(e^2-e^{-2}\right)-\left(e^0-e^{-0}\right) = \boxed{e^2-\frac1{e^2}}$

5 0

3 years ago

3.x2 + 4x + 5 for x = -2<br>please help asap

Law Incorporation [45]

Your equation is a little messed up comment me the equation you need help with

8 0

3 years ago