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ale4655 [162]
3 years ago
15

I will mark brainliest !

Mathematics
1 answer:
harina [27]3 years ago
4 0

Answer:

90 degrees

Step-by-step explanation:

A circle circumscribed over a right triangle is the same as a circle circumscribed over a rectangle built from the extension of the right triangle.

That tells us that the hypotenuse is the diameter of the circle in that case.

Here, we can see a triangle that has the hypotenuse as the diameter of the circumscribed circle. We can infer that the triangle is a right triangle.

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Keith_Richards [23]
All you do is divide by 10

there are 189 whole dimes
5 0
3 years ago
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Please help me solve this
In-s [12.5K]

Step-by-step explanation:

Erase the dot points you already have. We are supposed to substitute those values in the right side of problem 1 into the function as x.

For example if x=-4

- ( - 4) + 5 = 9

If x=-2

- ( - 2) + 5 = 7

If x=0

0 + 5 = 5

- 2 + 5 =  3

- 4 + 5 = 1

So our point should be

-4,9

-2,7

0,5

-2,3

-4,1.

The range is all possible y values in a function. Since this is discrete and we are given the domain, our range will just be the y value of the points you graphed.

(9,7,5,3,1)

5 0
2 years ago
Help me with these problems please
Scorpion4ik [409]
1. y = 7
2. 0
3. m = -1
4. k = -4
5. x = -6
6. There is no solution for these equations.

Please let me know if you want explanations/work shown!! Hope this helps :)
7 0
3 years ago
4 cos²x – 1=0<br><br> What is the solution?
andreev551 [17]

Answer:

$x=\frac{\pi }{3}+2\pi n, n\in \mathbb{Z}$

$\:x=\frac{5\pi }{3}+2\pi n, n \in \mathbb{Z}$

$x=\frac{2\pi }{3}+2\pi n, n\in \mathbb{Z}$

$\:x=\frac{4\pi }{3}+2\pi n, n \in \mathbb{Z}$

or

$x=\frac{\pi}{3}+\pi n, n \in \mathbb{Z} $

$x=\frac{2\pi }{3}+\pi n, n\in \mathbb{Z}$

Step-by-step explanation:

4\text{cos}^2(x)-1=0\\4\text{cos}^2(x)=1\\

$cos(x)=\pm\sqrt{\frac{1}{4} } $

$cos(x)=\pm\frac{1}{2}  $

So, when cos(x) is equal to

$\frac{1}{2}   \text{ and } -\frac{1}{2}$    ?

For

$cos(x)=\frac{1}{2} $

We are talking about x = 60º and x = 300º, Quadrant I and IV, respectively. In radians:

$x=\frac{\pi }{3}+2\pi n, n\in \mathbb{Z}$

$\:x=\frac{5\pi }{3}+2\pi n, n \in \mathbb{Z}$

or

$x=\frac{\pi}{3}+\pi n, n \in \mathbb{Z} $

For

$cos(x)=-\frac{1}{2} $

We are talking about x = 120º and x = 240º, Quadrant II and III, respectively. In radians:

$x=\frac{2\pi }{3}+2\pi n, n\in \mathbb{Z}$

$\:x=\frac{4\pi }{3}+2\pi n, n \in \mathbb{Z}$

or

$x=\frac{2\pi }{3}+\pi n, n\in \mathbb{Z}$

6 0
3 years ago
The table below shows the total cost of buying printer ink cartridges for both members and nonmembers of a shopping club. Price
ki77a [65]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
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