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serg [7]
4 years ago
10

Find the x and y coordinates of the position at which an electron would be in equilibrium.

Physics
1 answer:
love history [14]4 years ago
4 0
Let e be the charge of the electron.
Then F1 + F2 = 0
F1 = K (-1.5) * (-e) /r1^2
F2 = K (15) * (-e) /r2^2
(-1.5) * /r1^2 + (15) /r2^2 = 0
-1 /r1^2 + (10) /r2^2 = 0
[r2/r1]^2 = 10
[R2/r1] = ± 3.162
r2 = ± 3.162 r1.

Given r1 + r2 = √ [1^2 + 0.5^2] = 1.1180-----1
Also tan θ = 0.5 => θ = 26.57°
====================================
Substituting r2 = 3.162 r1 in 1
4.162 r1=1.1180
r1 = 0.2686 m

x coordinate = r1 cos θ = 0.2403 m
y coordinate = r1 sin θ = 0.1201m
===================================

Substituting r2 = - 3.162 r1 in 1
-2.162 r1=1.1180
r1 = -0.5171m
x coordinate = r1 cos θ = -0.4625m
y coordinate = r1 sin θ = -0.2313m
===============================
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2 years ago
(Part 1 of 3)
Ksju [112]

1) 1.028 m/s^2

We can solve this part by using Newton's second law:

F=ma (1)

where

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m is the mass

a is the acceleration

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F_1= 2.90 \cdot 10^3 N forward

F_2 = 1.69\cdot 10^3 N backward

So the net force is

F=2.90\cdot 10^3-1.69\cdot 10^3=1.21\cdot 10^3 N

We know that the mass of the boat is

m = 1177.5 kg

So we can now use eq.(1) to find the acceleration:

a=\frac{F}{m}=\frac{1.21\cdot 10^3}{1177.5}=1.028 m/s^2

2) 161.0 m

We can solve this part by using the following suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance travelled

u is the initial velocity

t is the time

a is the acceleration

Here we have

u = 0 (the boat starts from rest)

a=1.028 m/s^2

Substituting t = 17.7 s, we find the distance covered:

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3) 18.2 m/s

The speed of the boat can be found with the following suvat equation

v=u+at

where

v is the final velocity

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In this case we have

u = 0 (the boat starts from rest)

a=1.028 m/s^2

And substituting t = 17.7 s, we find the final velocity:

v=0+(1.028)(17.7)=18.2 m/s

And the speed is just the magnitude of the velocity, so 18.2 m/s.

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