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Andre45 [30]
2 years ago
10

Help plz it would be nice!

Mathematics
1 answer:
melamori03 [73]2 years ago
6 0
You add 70,50, and 90 together then you do seperately 30, and80 (add) lastly take that amount then divide that by your first sum
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What is the sum of all the exterior angles for a 99-gon?*
mars1129 [50]

Answer:

360

Step-by-step explanation:

The sum exterior angles of any number of side polygon is always 360

8 0
3 years ago
The value of the expression 2(3) +3(2)–3x4–5(2)-5+(7x4) is
Sliva [168]

Answer: the answer is 46

Step-by-step explanation:

8 0
2 years ago
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Given that (x,y) = (5,15) find tan Ø. <br><br> A. 3 <br> B. 1/3 <br> C. 5 <br> D. 1/5
lesantik [10]
This value is in the positive quadrant meaning that all values remain positive. To answer this problem you must have an understanding of trig ratios being that tangent is opposite/adjacent. When you plot the points and draw a triangle using the origin of the point, you find that the adjacent value is 5 and opposite value is 15
7 0
3 years ago
Rob laid three sticks end to end. The lengths of the sticks were 45 millimeters, 32 centimeters, and 4 decimeters. How long, in
Oksanka [162]

Answer:

<u>0.765 meters</u> long were the sticks when laid end to end.

Step-by-step explanation:

Given:

Rob laid three sticks end to end. The lengths of the sticks were 45 millimeters, 32 centimeters, and 4 decimeters.

Now, to find the length in meters of the sticks when laid end to end.

The lengths of the sticks are:

1st stick - 45 millimeters.

2nd stick - 32 centimeters.

3rd stick - 4 decimeters.

So, we convert the units of sticks into meters by using conversion factor:

1st stick:

1 millimeter = 0.001 meter.

45 millimeters = 0.001 × 45

45 millimeters = 0.045 meter.

2nd stick:

1 centimeter = 0.01 meter.

32 centimeters = 0.01 × 32

32 centimeters = 0.32 meter.

3rd stick:

1 decimeter = 0.1 meter.

4 decimeters = 0.1 × 4

4 decimeters = 0.4 meter.

Now, adding all the three sticks length to get the the length in meters of the sticks when laid end to end:

0.045+0.32+0.4\\\\=0.765\ meters.

Therefore, 0.765 meters long were the sticks when laid end to end.

5 0
3 years ago
Find a quadratic polynomial with integer coefficients which has x = 2/9, ± SQRT23/9 as its real zeros.
melomori [17]

Answer:

The quadratic polynomial with integer coefficients is y = 81\cdot x^{2}-36\cdot x -19.

Step-by-step explanation:

Statement is incorrectly written. Correct form is described below:

<em>Find a quadratic polynomial with integer coefficients which has the following real zeros: </em>x = \frac{2}{9}\pm \frac{\sqrt{23}}{9}<em>. </em>

Let be r_{1} = \frac{2}{9}+\frac{\sqrt{23}}{9} and r_{2} = \frac{2}{9}-\frac{\sqrt{23}}{9} roots of the quadratic function. By Algebra we know that:

y = (x-r_{1})\cdot (x-r_{2}) = x^{2}-(r_{1}+r_{2})\cdot x +r_{1}\cdot r_{2} (1)

Then, the quadratic polynomial is:

y = x^{2}-\frac{4}{9}\cdot x -\frac{19}{81}

y = 81\cdot x^{2}-36\cdot x -19

The quadratic polynomial with integer coefficients is y = 81\cdot x^{2}-36\cdot x -19.

5 0
2 years ago
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