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kow [346]
3 years ago
8

Find r if 2700=2200(1+r)ˆ5 ( ˆ5 is the exponent for 5 )

Mathematics
1 answer:
Leviafan [203]3 years ago
4 0
2700=2200(1+r)^5 \ /:2200\\\\(1+r)^5= \frac{27}{22} \\\\1+r= \sqrt[5]{\frac{27}{22} } \\\\r=\sqrt[5]{\frac{27}{22} } -1
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Answer:

The original fraction is \frac{6}{14}.

Step-by-step explanation:

Solution,

Let the fraction be'\frac{x}{y}'.

Where 'x' is the numerator and 'y' is the denominator.

Now according to question, if 2 is added to both the numerator and denominator the value of the fraction becomes 1/2.

So, framing the above sentence in equation form, we get;

\frac{x+2}{y+2}=\frac{1}{2}

On using cross multiplication method, we get;

2(x+2)=y+2\\\\2x+4=y+2\\\\2x+4-2=y\\\\\therefore\ y=2x+2\ \ \ \ equation\ 1

Now according to question, if 2 is Subtracted to both the numerator and denominator the value of the fraction becomes 1/3.

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On using cross multiplication method, we get;

3(x-2)=y-2\\\\3x-6=y-2\\\\3x-y=-2+6\\\\3x-y=4 \ \ \ \ equation\ 2

Now Substituting the equation 1 in equation 1 we get;

3x-y=4\\\\3x-(2x+2)=4\\\\3x-2x-2=4\\\\3x-2x=4+2\\\\x=6

Now Substituting the value of x in equation 1 we get;

y=2x+2\\\\y=2\times6+2 = 14

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