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oksano4ka [1.4K]
3 years ago
15

How do I do this question

Mathematics
1 answer:
Setler [38]3 years ago
5 0
You could use the shadow made by the tower. For this you would need the length of the shadow and the hypotenuse of the triangle created. As for a picture of it you can just make a line and label it as a tower, then a line underneath as the shadow length then just connect the two lines forming a triangle that will be the hypotenuse.
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Approximate: log 5 ^4/7
wolverine [178]

Do you mean the following:

log(5^(4/7))=around 0.4

log(5)^(4/7)=around 0.815

log(5^4)/7= same thing as top one

log((5^4)/7)=around 1.95

6 0
4 years ago
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If your correct i will give u brainlist=)
morpeh [17]

Answer:

point m' translated down 6 units

Step-by-step explanation:

4 0
3 years ago
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What is the product of 2x
Irina18 [472]

Answer:

2x

Step-by-step explanation:


2x if you don't know the value of x.

5 0
4 years ago
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Gasoline prices for the first six months of 2004 are shown in the table below. Using a logarithmic model, what is the best
Molodets [167]

Answer:

A) $2.10

Step-by-step explanation:

I got it right on edge

5 0
3 years ago
How many real solutions if any, does 2x^2-3x+8=0​
fenix001 [56]

Answer:

The quadratic equation 2\, x^{2} - 3\, x + 8 = 0 has no real solution.

Step-by-step explanation:

Rewrite the quadratic equation 2\, x^{2} - 3\, x + 8 = 0 in the standard form a\, x^{2} + b\, x + c = 0:

2\, x^{2} + (-3)\, x + 8 = 0, for which:

  • a = 2.
  • b = (-3).
  • c = 8.

The quadratic discriminant of a\, x^{2} + b\, x + c = 0 is (b^{2} - 4\, a\, c).  The quadratic discriminant of 2\, x^{2} + (-3)\, x + 8 = 0 would be:

\begin{aligned}& b^{2} - 4\, a\, c \\ =\; & (-3)^{2} - 4 \times 2 \times 8 \\ =\; & (-55)\end{aligned}.

Since the quadratic discriminant of this equation is negative, this quadratic equation has no real solution.

3 0
2 years ago
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