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Vinil7 [7]
3 years ago
14

The English class has half as many students as the math class

Mathematics
1 answer:
likoan [24]3 years ago
6 0
If you are looking for an equation to solve it, it is E=m/2
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Irina-Kira [14]

Answer:

The answer is x= -10

3 0
3 years ago
This assignment is an exit ticket so yah lol
Schach [20]

Answer: #1 is that It is warmer on Monday then Tuesday #2 -.1 because It is warmer the Tuesday without being over 0

Step-by-step explanation:

6 0
3 years ago
The vertex of a parabola is ( 3, -1). One point on the parabola is
Rudik [331]

Answer:

Step-by-step explanation:

If you plot the vertex and the point, you see that the point is above the vertex. Therefore, this is a positive parabola with the work form of

y=a(x-h)^2+k

We have values for x, y, h, and k. Let's write the equation of the parabola, put it into function notation, then find another x value at which to evaluate it.

8=a(6-3)^2-1 and

8=a(3)^2-1 and

8 = 9a - 1 and

9 = 9a so

a = 1. The equation of the parabola in function notation is

f(x)=(x-3)^2-1

Since the vertex is at (3, -1) it would make sense to evaluate the function at x values close to the vertex. Let's evaluate the function at an x value of 4:

f(4)=(4-3)^2-1 and

f(4)=(1)^1-1 and

f(4) = 0. That means that another point on this parabola will be (4, 0).

8 0
4 years ago
Let a= x^2 +4. Rewrite the following equation in terms of a and set it equal to zero.
dusya [7]

Answer:


If:

a=x^{2}+4    (1)


And we have to rewrite the following expresion in terms of a:


{(x^{2}+4)}^{2}+32=12x^{2}+48   (2)


Firstly we have to rearrange the right side of equation (2) in terms of  x^{2}+4, factorizing by the common factor:


{(x^{2}+4)}^{2}+32=12(x^{2}+4)


Then, we can substitute x^{2}+4 by a:


a^{2}+32=12a


And set it equal to zero:

a^{2}-12a+32=0>>>>This is the resulting equation


Now, each term of an algebraic expresion (like the equation above) is composed of sign, coefficient, variable and exponent. The terms are separated from each other by the plus sign (+) or the minus sign (-).



In this case, the variable is a and the number that multiplies the variable (the coefficient) is -12, whereas the constant (which is the term with no variable) is 32





6 0
3 years ago
Read 2 more answers
I’m confused on this question
aksik [14]
The answer is Quadrant 4
4 0
3 years ago
Read 2 more answers
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