All categories

3 years ago

Evaluate the expression:–|20| + |5|

1 answer:

3 0

-|20| + |5| = -15

Steps:
Apply absolute rule: |a| = a, a >/ 0
|20| = 20
= -20+5
Apply absolute rule: |a| = a, a >/ 0
|5| = 5
= -20+5
Refine
= -15

Hope this helps you! (:
-Hamilton1757

You might be interested in

What is the number that is two more than one-tenth of one-fifth of one-tenth of 2,000

topjm [15]

Answer:

Step-by-step explanation:

2 + (1/10)(1/5)(1/10)2000 = 2 + (1/500)(2000) = 2 + 4 = 6

6 0

2 years ago

Which of the following is an example of the compliment rule being applied to

UNO [17]

Answer:

Hello There!!

Step-by-step explanation:

I think the answer is B. The probability of not drawing a club or jack from a deck of cards.

hope this helps,have a great day!!

~Pinky~

6 0

2 years ago

Read 2 more answers

If the image above is rotated about the y-axis, which of the following images best represents the result?

swat32

Answer:

the answer would be x because it has a larger width than y

6 0

2 years ago

Please help!! MathsWatch, Surd Expressions, Clip 207c

dexar [7]

Answer:

$A=(72+36\sqrt{3})\ mm^2$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

a ----> the height of rectangle in mm

b ---> the base of rectangle in mm

step 1

Find the base of rectangle

$b=AB+BC+CD+DE$ ----> by segment addition postulate

substitute

$b=3+3+3+3=12\ mm$

step 2

Find the height of rectangle

$a=FB+CG+GH$ ---> by segment addition postulate

substitute the given values

$a=3+CG+3\\a=6+CG$

Find the length sides CG

Applying the Pythagorean Theorem

$BG^2=BC^2+CG^2$

substitute the given values

$6^2=3^2+CG^2$

$CG^2=6^2-3^2$

$CG=\sqrt{27}\ mm$

simplify

$CG=3\sqrt{3}\ mm$

therefore

$a=(6+3\sqrt{3})\ mm$

step 3

Find the area of rectangle

$A=ab$

we have

$a=(6+3\sqrt{3})\ mm$

$b=12\ mm$

substitute

$A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2$

8 0

3 years ago

,mmnj3gohb4yvgbuh4rbihb3rvhbeffhobvouwebohbewovjdkcbhoebfvhubefhvbhuewfbviohbefwovbehbvhebfphbpvibepivb4uhbvuohebfvhubefubvuhrb4

RSB [31]

Answer:

jdkskdjdjfnfnekeoeodnfnfnn;#>#[<:<:÷_9:÷8÷8_:>^:#<:8÷^8<#9<^g9su9ugsvy9e9uebu93vy838y3vy038j3b7496g4b79468g4bu940bev9urbd0ubdb0iuv0d0ibdv0ud9vy3 yv83 8y38 y y88_:-;0<#9_%;3636:04:9649660:3:_939_:$<$:9<#0;#_9^#:9<

7 0

3 years ago

Read 2 more answers