That would be the slope of this straight line; it's 30 units / lesson, e. g., $30/lesson. The $25 is the registration and/or up-front cost.
Answer: 5/14
--------------------------------------------------
Explanation:
A = event of drawing a blue card on the first selection
B = event of drawing a blue card on the second selection
P(A) = probability of drawing a blue card on the first selection
P(A) = (number of blue cards)/(number of cards total)
P(A) = 5/8
P(B|A) = probability of getting a second blue card GIVEN the first card is blue
P(B|A) = (number of blue cards left after event A happens)/(number of cards left)
P(B|A) = 4/7
The fact that B depends on A is very important. This happens because the first card is not replaced
Multiply the fractions
P(A)*P(B|A) = (5/8)*(4/7)
P(A)*P(B|A) = (5*4)/(8*7)
P(A)*P(B|A) = 20/56
P(A)*P(B|A) = 5/14
Which is why the answer is the fraction 5/14
Answer:
16.5 units
Step-by-step explanation:
The midsegment is the distance between the midpoints of the nonparallel sides of the trapezoid.
The trapezoid ABCD has vertices A(1,6) B(-2,6) C(-10,-10) and D(20,-10).
We want to find the midsegment of ABCD to the nearest tenth.
The midpoint of BC is;
The midpoint of AD is :
The length of the midsegment is the distance from (-6,2) to (10.5,2)
Note that c is the hypotenuse of the blue triangle, and that the Pyth. Thm. states that (length of one leg)^2 + (length of the other leg)^2 = (hyp)^2.
Therefore, (hyp)^2 = c^2 = [2sqrt(x^2+3x)]^2 + 3^2, or
= 4(x^2+3x) + 9, or
= 4x^2 + 12x + 9 = (2x+3)^2
Taking the sqrt of both sides, c = plus or minus (2x+3). Eliminate -(2x+3) because the middle term of the square of this would be negative, in conflict with the given +12x.
c=2x+3 is the correct answer.
