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ICE Princess25 [194]
3 years ago
14

A line includes the points (9, -7) and (-6, -2). What is its equation in slope-intercept form?

Mathematics
1 answer:
Rus_ich [418]3 years ago
8 0

Answer:

y=\frac{-1}{3}x-4

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

<em>m</em> - slope

<em>b </em>- y-intercept

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step 1: Define

Point (9, -7)

Point (-6, -2)

Step 2: Find slope <em>m</em>

<em />m=\frac{-2-(-7)}{-6-9}<em />

<em />m=\frac{-2+7}{-15}<em />

<em />m=\frac{5}{-15}<em />

<em />m=\frac{-1}{3}<em />

y=\frac{-1}{3}x+b

Step 3: Find y-intercept <em>b</em>

<em />-7=\frac{-1}{3}(9)+b<em />

<em />-7=-3+b<em />

<em />-4=b<em />

<em />

Step 4: Write linear equation in slope-intercept form

y=\frac{-1}{3}x-4

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The simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

<h3>How to simplify the expression?</h3>

The expression is given as:

\sqrt{\frac{162x^9}{2x^{27}}}

Divide 162 and 2 by 2

\sqrt{\frac{81x^9}{x^{27}}}

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Apply the quotient rule of indices

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Evaluate the difference

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