Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
Answer:
-2/3 is the y intercept
Step-by-step explanation:
So to find the y-intercept you must first put this in Slope-intercept form, I believe the form it is in right now is called standard form.
To get it into slope intercept form, we have to isolate y:
subtract 2x from both sides:
-3y = -2x + 2
Divide both sides by -3:
y = (2/3)x - 2/3
Now that we have slope-intercept form, we can find the y-intercept. We know slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. In this case the y-intercept is -2/3.
Hope this helps!
Answer:
214....
Step-by-step explanation:
If the question is : solve 4 by 216 raise to minus 2 by 3 + 1 by 256 raise to minus 3 by 4 + 2 by 243 raise to minus 1 by 5
The given expression can be written as:
4/(216)-2/3+1/(256)-3/4+2/(243)-1/5
This expression has three terms.
Notice that the exponents are negative:
We will change the division into multiplication so that the exponents will become positive;
4*(216)^2/3+ 1*(256)^3/4+ 2*(243)^1/5
If we multiply 6 three times it will give us 6^3=6*6*6=216
If we multiply 4 four times it will give us 4^4=4*4*4*4=256
If we multiply 3 five times it will give us 3^5=3*3*3*3*3=243
So we will write it as:
=4*(6^3)^2/3+ 1(4^4)3/4 +2(3^5)^1/5
=4(6)^2+(4)^3+2(3)
=4*36+64+6
=144+64+6
=214
The answer is 214....
