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Oksanka [162]
3 years ago
5

I need answers about those mathematic problem

Mathematics
1 answer:
Alexandra [31]3 years ago
7 0

Answer:

10) -24

11) -15

12 -56

13) -7

14) 175

15) -7

16) 80

17) -25

Step-by-step explanation:

Hope i could help you in time:)

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Write y=1/6x+7 in standard form using intergers.​
Anna71 [15]

Answer:

–x + 6y = 42

Hope this answer is right!

4 0
3 years ago
The sum of the areas of two circles is 80n square meters. Find the length of a radius of each circle if
astra-53 [7]

Answer:

8 meters.

Step-by-step explanation:

Let the 2 radii be x and 2x, then
π x^2 + π (2x)^2 = 80π

π x^2 + π 4x^2= 80π

x^2 + 4x^2= 80

5x^2 = 80

x^2 = 16

x = 4.

So the radius of the larger circle = 2*4 = 8 m.

4 0
2 years ago
Expand the expression and combine like terms: 2(−14+r)−(−3r−5)
Serggg [28]
2r-20 is the answer combining the like terms and solving.
4 0
3 years ago
What is the result when x4 – 723 – 13x2 – 2x + 7 is divided by x + 1? If there is
deff fn [24]
Can you post a picture please!
6 0
3 years ago
From a group of 13 women and ​12 men, a researcher wants to randomly select 8 women and 8 men for a study. In how many ways can
Fantom [35]

The total number of ways the study can be selected is: 637065

Given,

Total number of women in a group= 13

Total number of men in a group = 12

Number of women chosen = 8

Number of men chosen = 8

∴ the total number of ways the study group can be selected = 13C₈ and 12C₈.

This in the form of combination factor = nCr

                                                     ∴ nCr = n!/(n₋r)! r!

13C₈ = 13!/(13 ₋ 8)! 8!

        = 13!/5!.8!

        = 1287

12C₈ = 12!/(12₋8)! 8!

        = 12!/5! 8!

        = 495

Now multiply both the combinations of men and women

= 1287 × 495

= 637065

Hence the total number of ways the study group is selected is 637065

Learn more about "Permutations and Combinations" here-

brainly.com/question/11732255

#SPJ10

4 0
2 years ago
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