Question

Which inequality will have a solid boundary line and a shaded region above its graph?

Answer 1

Answer:

B. 2x − 3y ≤ 3

Step-by-step explanation:

We are required to find the graph having solid boundary line.

When a graph have soled boundary line. Then, the inequality will have the equality sign in it.

That is, strict inequality can never have a solid boundary line.

So, option C and D are discarded.

Further, the graph must have shaded region above the graph.

Now, the region above the graph means that, the inequality must be of the form $y > ax+b$.

So, we have,

$x-y\geq 3$ implies $y\leq x-3$

So, option A is not correct.

But, $2x-3y\leq 3$ implies $y\geq \frac{2x}{3}-1$

Thus, the inequality having solid boundary and graph above is $2x-3y\leq 3$.

Answer 2

A solid line means either ≥ or ≤

So either A or B
 
Above the graph: Must be greater than y

B