Answer:
option a is correct
net force = 28.7 N and 70º
Explanation:
given data
first force= 17.0 N
angle = 58.0º
2nd force = -19.0 N and 12.5 N
to find out
magnitude and direction net force
solution
we know here 1st force is at angle 58.0º is 17 N
so here x component of force is F1 cosθ and y component of force is F1 sinθ
so 1st force
x component of force = F1 cosθ = 17 cos(58) = 9.0086 N ...............1
y component of force = F1 sinθ = 17 sin(58) = 14.4168 N ..............2
and 2nd force
x component of force = -19 N .................3
y component of force = 12.5 N ..................4
so net force is
net force = √(Fx²+Fy²)
net force = √((9-19)²+(14.41+12.5)²)
net force = 28.7 N
and
magnitude
tanθ = Fy / Fx
tanθ = 26.92 / 10
θ = 70º
so option a is correct
It takes 4.58 seconds for the car to stop and the initial speed of the car is 77.14 ft/s
<u>Explanation:</u>
Given:
Acceleration, a = -17 ft/s²
Distance, s = 175 ft
Final velocity, v = 0
Time, t = ?
Initial speed, u = ?
We know:
v² - u² = 2as
(0)² - (u)² = 2 X - 17 X 175
u² = 5950
u = 77.14 ft/s
To calculate time:
v = u + at
0 = 77.14 - 17 X t
17t = 77.14
t = 4.58 sec
Therefore, It takes 4.58 seconds for the car to stop and the initial speed of the car is 77.14 ft/s
Convert km to m. -> 320km=320000 m
Convert hours to seconds -> 4 hrs=14400 s
Divide the distance by time because v=d/t
320000/14400=22.22 m/s
One cubic centimeter and one milliliter are equal volumes.