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2 years ago

7

A rock is thrown straight upward off the edge of a balcony that is 5 m above the ground. The rock rises 10 m, then falls all the

way down to the ground below the balcony. What is the rock's displacement?

1 answer:

Dvinal [7]2 years ago

7 0

Displacement = distance and direction from the start-point
to the end-point, regardless of the route followed on the way.

From the throw to the 'plop', the displacement is 5 meters down.

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A person measures his or her heart rate by counting the number of beats in 30s. If 40±1 beats are counted in 30.0±0.5s, what is

nordsb [41]

Answer:

$Rate = 1.33 \pm 0.055$ beats per second

Explanation:

Number of heart beats = $40 \pm 1$

time taken = $30.0 \pm 0.5 s$

now we have

$N = 40 \pm 2.5$ %

$t = 30.0 \pm 1.67$ %

now rate of heart beat is defined as number of heart beat per unit of time

so we have

$Rate = \frac{N}{t}$

$Rate = \frac{40 \pm 2.5}{30 \pm 1.67}$

so we have

$Rate = 1.33 \pm (2.5 + 1.67 )$

$Rate = 1.33 \pm 4.17$ %

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2 years ago

please help! find magnitude and direction (the counterclockwise angle with the +x axis) of a vector that is equal to a + c

-BARSIC- [3]

Answer:

Option (2)

Explanation:

From the figure attached,

Horizontal component, $A_x=A\text{Sin}37$

$A_x=12[\text{Sin}(37)]$

= 7.22 m

Vertical component, $A_y=A[\text{Cos}(37)]$

= 9.58 m

Similarly, Horizontal component of vector C,

$C_x$ = C[Cos(60)]

= 6[Cos(60)]

= $\frac{6}{2}$

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$C_y=6[\text{Sin}(60)]$

= 5.20 m

Resultant Horizontal component of the vectors A + C,

$R_x=7.22-3=4.22$ m

$R_y=9.58-5.20$ = 4.38 m

Now magnitude of the resultant will be,

From ΔOBC,

$R=\sqrt{(R_x)^{2}+(R_y)^2}$

= $\sqrt{(4.22)^2+(4.38)^2}$

= $\sqrt{17.81+19.18}$

= 6.1 m

Direction of the resultant will be towards vector A.

tan(∠COB) = $\frac{\text{CB}}{\text{OB}}$

= $\frac{R_y}{R_x}$

= $\frac{4.38}{4.22}$

m∠COB = $\text{tan}^{-1}(1.04)$

= 46°

Therefore, magnitude of the resultant vector will be 6.1 m and direction will be 46°.

Option (2) will be the answer.

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2 years ago

Acceleration and Force

olga55 [171]

Answer:

I'm pretty sure its 3m/s^2 for the acceleration but I don't know the force part sorry .

Explanation:

15m/s - 0m/s divided by 5 s = 3m/s

I'm no expert or anything so I could be wrong but this is the best I can give you. Sorry

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1 year ago

A train travels 200km/hr. how much distance will the train be from the station in 2.5 hours?

SCORPION-xisa [38]

Answer:

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Given parameters:

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Time taken = 2.5hrs

Unknown:

Distance = ?

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To solve this problem, we use the speed, time and distance equation.

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1 year ago

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Nezavi [6.7K]

The change in velocity is +4 m/s to the right (or -4 m/s to the left).

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2 years ago