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solong [7]
3 years ago
7

A rock is thrown straight upward off the edge of a balcony that is 5 m above the ground. The rock rises 10 m, then falls all the

way down to the ground below the balcony. What is the rock's displacement?
Physics
1 answer:
Dvinal [7]3 years ago
7 0
Displacement = distance and direction from the start-point
to the end-point, regardless of the route followed on the way.

From the throw to the 'plop', the displacement is 5 meters down.
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A truck covers 40.0 m in 7.45 s while uniformly slowing down to a final velocity of 3.50 m/s.
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Answer:

(A) Original velocity will be 7.244 m /sec

(B) Acceleration will be  -0.5026m/sec^2

Explanation:

We have given distance covers by truck s = 40 m

Time taken by truck to cover this distance t = 7.45 sec

Final velocity v = 3.50 sec

According to second equation of motion

S=ut+\frac{1}{2}at^2

40=u\times 7.45+\frac{1}{2}\times a\times 7.45^2

7.45u+27.751a=40-----eqn 1

According to first equation of motion

v = u + at

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Solving equation 1 and 2

a = -0.5026m/sec^2

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(A) Original velocity will be 7.244 m /sec

(B) Acceleration will be

-0.5026m/sec^2

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