All categories

3 years ago

Please answer the question.

Mathematics

1 answer:

Maksim231197 [3]3 years ago

7 0

Answer:

Every number is rational except for pi

Step-by-step explanation:

You might be interested in

On a scatter plot, what does it mean when both variables are increasing?

Elodia [21]

When both variables increase together, a line can be made to represent their constant rise. This means that there is a positive correlation between the two, as one increases or decreases with the other.

The answer is A. positive correlation.

4 0

3 years ago

Read 2 more answers

Help will give Brainly points

Alexandra [31]

Answer:

Use the SINE RULE:

$\frac{a}{ \sin( \alpha ) } = \frac{b}{ \sin( \beta ) }$

$\frac{6}{ \sin(60) } = \frac{x}{ \sin(90) }$

$x = \sin(90) \times \frac{6}{ \sin(60) }$

$x = 6.93$

5 0

3 years ago

9x5000x9x how many thousands

melisa1 [442]

Answer:

Step-by-step explanation:

5000X9X9=405000x

5 0

3 years ago

Which of the following functions best describes this graph?

Brrunno [24]

Answer:

i think it is a

Step-by-step explanation:

8 0

3 years ago

Use the laplace transform to solve the given system of differential equations. dx dt + 3x + dy dt = 1 dx dt − x + dy dt − y = et

blagie [28]

Let $X(s)$ and $Y(s)$ denote the Laplace transforms of $x(t)$ and $y(t)$ .

Taking the Laplace transform of both sides of both equations, we have

$\dfrac{dx}{dt} + 3x + \dfrac{dy}{dt} = 1 \implies \left(sX(s) - x(0)\right) + 3X(s) + \left(sY(s) - y(0)\right) = \dfrac1s \\\\ \implies (s+3) X(s) + s Y(s) = \dfrac1s$

$\dfrac{dx}{dt} - x + \dfrac{dy}{dt} = e^t \implies \left(sX(s) - x(0)\right) - X(s) + \left(sY(s) - y(0)\right) = \dfrac1{s-1} \\\\ \implies (s-1) X(s) + s Y(s) = \dfrac1{s-1}$

Eliminating $Y(s)$ , we get

$\left((s+3) X(s) + s Y(s)\right) - \left((s-1) X(s) + s Y(s)\right) = \dfrac1s - \dfrac1{s-1} \\\\ \implies X(s) = \dfrac14 \left(\dfrac1s - \dfrac1{s-1}\right)$

Take the inverse transform of both sides to solve for $x(t)$ .

$\boxed{x(t) = \dfrac14 (1 - e^t)}$

Solve for $Y(s)$ .

$(s - 1) X(s) + s Y(s) = \dfrac1{s-1} \implies -\dfrac1{4s} + s Y(s) = \dfrac1{s-1} \\\\ \implies s Y(s) = \dfrac1{s-1} + \dfrac1{4s} \\\\ \implies Y(s) = \dfrac1{s(s-1)} + \dfrac1{4s^2} \\\\ \implies Y(s) = \dfrac1{s-1} - \dfrac1s + \dfrac1{4s^2}$

Taking the inverse transform of both sides, we get

$\boxed{y(t) = e^t - 1 + \dfrac14 t}$

7 0

1 year ago