3 years ago

The sum of 4 times a number and 3 is 9

Mathematics

1 answer:

nalin [4]3 years ago

3 0

Answer:

x = 6/4 or 1 1/2

Step-by-step explanation:

4x+3=9

Subtract the 3 from both sides

4x+3=9

-3 -3

4x = 6

Divide both sides by 4

x = 6/4 or 1 1/2

You might be interested in

What are two numbers that add to make 36 with one of the numbers be exactly twice the other

Tema [17]

To solve, set an equation:
First Number: x
Second Number: 2x

x+2x=36
3x=36
divide both sides by 3
x=13

First Number: (x) 12
Second Number: (2x) 24

Answers: 12 and 24

3 0

3 years ago

Read 2 more answers

When a shape is dilated, the _________ of the lengths in the image to the corresponding lengths in the pre-image are equal to th

Burka [1]

When a shape is dilated the RATIOS of the lengths in the image to the corresponding lengths in the preimage are equal to the scale factor

4 0

3 years ago

Select all of the following that are like radicals.<br> 9./6ab2<br> -5./6ab2<br> 436ab2<br> 2 V6b²a

Marizza181 [45]

Answer:

i did it on ed

4 0

3 years ago

If the numbers 25, 30 ,40, 48 are in proportion, Middle terms are.....

zubka84 [21]

Step-by-step explanation:

it is 5/6 ..............

3 0

3 years ago

Timothy is 13 5/6 years old. Camden is 1 1/3 years younger than Timothy and Jane is 1 1/4 years younger than Camden. How old is

galina1969 [7]

Answer:

Jane is 11 1/4 years old.

Step-by-step explanation:

Subtract all of the numbers given.

$13\frac{5}{6} -1\frac{1}{3} -1\frac{1}{4}$ .

To subtract this, we need to find a common denominator.

A common denominator in this situation is 12. To do this multiply the 5 and the 6 of 5/6 by 2. Multiply the 1 and the 3 of 1/3 by 4. And multiply the 1 and the 4 1/4 by 3.

The new expression will look like this:

$13\frac{10}{12} -1\frac{4}{12} -1\frac{3}{12}$ .

Now we can subtract.

$13\frac{10}{12} -1\frac{4}{12} -1\frac{3}{12}=11\frac{3}{12}$

Reduce the answer.

$11\frac{3}{12}=11\frac{1}{4}$

In decimal form 11.25

Hope this helps!

If not, I am sorry.

5 0

2 years ago