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Mathematics

1 answer:

marin [14]3 years ago

7 0

I blieve answer is A........mmmmmmmmmmmm

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Solve this equation pls

Aleksandr-060686 [28]

Answer:

${ \rm{y = \frac{3 \sqrt{x} + 2x}{ {4x}^{2} } }} \\$

• We are gonna use the quotient rule

${ \boxed{ \bf{ \frac{dy}{dx} = \frac{ {\huge{v} } \frac{du}{dx} - { \huge{u}} \frac{dv}{dx} }{ {v}^{2} } }}} \\$

u is (3√x + 2x)
v is 4x²
du/dx is 3/2√x
dv/dx is 8x

• Therefore:

${ \rm{ \frac{dy}{dx} = \frac{(4 {x}^{2})( \frac{3}{2 \sqrt{x} }) - (3 \sqrt{x} + 2x)(8x) }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = \frac{(6 {x}^{2})( {x}^{ - \frac{1}{2} } ) - (24 {x}^{ \frac{3}{2} } + 16 {x}^{2} ) }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = \frac{ 6 {x}^{ \frac{3}{2} } - {24x}^{ \frac{3}{2} } - {16x}^{2} }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = \frac{ - 18 {x}^{ \frac{3}{2} } - 16 {x}^{2} }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = - 2 {x}^{ \frac{3}{2} } (9 + 8 {x}^{ \frac{4}{3} } ) \div 16 {x}^{4} }} \\ \\ { \boxed{ \boxed{ \rm{ \: \: \frac{dy}{dx} = - \frac{8 \sqrt{ {x}^{ \frac{8}{3} }} + 9}{8x {}^{ \frac{8}{3} } } \: \: }}}}$

5 0

2 years ago

Read 2 more answers

A survey 50 randomly selected students showed that 38 students by lunch at school and 12 students bring lunch from home each day

masha68 [24]

12/50=24% of student bring lunch so 24%-524=398 student buy lunch out of 524

8 0

2 years ago

Find the orthocenter of the triangle with the given vertices: L(2, 2), M(-4, 2), N(-2, 6) a (-2, 4) b (3, -5) c (2, -4) d (-3, 5

Norma-Jean [14]

9514 1404 393

Answer:

(a) (-2, 4)

Step-by-step explanation:

The orthocenter is the point of concurrence of the altitudes of the triangle.

A plot of the triangle vertices shows the triangle to be acute. That means the orthocenter is inside. This eliminates choices B, C, D, which are all points outside the triangle.

Conveniently, side LM is horizontal. This means the orthocenter will have the x-coordinate of the vertical line through N, which is -2. Only one answer choice has an x-coordinate of -2:

a (-2, 4)