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Juliette [100K]
3 years ago
14

What formula can be used to determine the velocity of an object in free fall?

Physics
1 answer:
PtichkaEL [24]3 years ago
4 0
Assuming that you're given either an initial or final velocity, you can use the following equation and solve for the initial or final velocity. 

Vyf² = Vyi² - 2g(y - y₀)

Where, 
Vyf² = final velocity
Vyi₂² = initial velocity
g = 9.81 m/s²
(y - y₀) = the change in the distance along the y-axis.

You'll need also determine the positive and negative of your y-axis for your final solution because velocity can be positive or negative based on direction. Lastly, don't forget to square root both sides of your equation for your velocity. 

I hope this helps. 
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4. A massless spring hangs from the ceiling, and a mass is hung from the bottom of it. The mass is supported
MrRissso [65]

Answer:

The correct option is C: 0.31 s.

Explanation:

When the mass is then suddenly released we have:

F = k\Delta y

Where:

F is the force

k: is the spring constant

Δy: is the spring displacement

Since the tension in the spring is zero, the force is the weight:

F = mg

Where:

m is the mass of the object

g is the gravity

mg = k\Delta y    (1)

The oscillation period of the spring is given by:

T = 2\pi \sqrt{\frac{m}{k}}    (2)

By solving equation (1) for "k" and entering into equation (2) we have:

T = 2\pi \sqrt{\frac{m}{\frac{mg}{\Delta y}}}

T = 2\pi \sqrt{\frac{\Delta y}{g}}

Since the spring will osclliates in a position between the initial position (when it is at rest) and the final position (when the mass is released and reaches the bottom), we have Δy = 2.5 cm = 0.025 m:

T = 2\pi \sqrt{\frac{0.025 m}{10 m/s^{2}}} = 0.31 s                   

Hence, the oscillation period is 0.31 s.

The correct option is C: 0.31s.

I hope it helps you!                                                                                                      

7 0
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RUDIKE [14]

Answer:

2000years

Explanation:

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6 0
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