Answer:
yes, They will be able to move the dresser.
Explanation:
sliding force 90N
55N + 38N = 93N
therefore, yes the twins can move the dresser
We'll just consider the down trip, from when it was at its highest point to when it hits the ground. Initial velocity is 0 m/s, acceleration is 9.81 m/s^2 (gravity), and time is 5.6s.
One of the kinematic equations is d = (Vi)(t) + 0.5(a)(t^2).
Plugging it in gives us d = 0 + (0.5)(9.81)(5.6^2) = 153.8208 m.
Hope this helped!
Decibels I believe? I’m not 100% sure
B, C, and D.
Solar energy is green energy, it wouldn't contribute to global warming. However some places of the world don't receive as much sunlight (the poles) and at night you don't receive as much sunlight either. Solar energy is also very expensive to farm.
Answer:
I = 69.3 μA
Explanation:
Current through the straight wire, I = 3.45 A
Number of turns, N = 5 turns
Diameter of the coil, D = 1.25 cm
Resistance of the coil, ![R = 3.25 \mu ohms](https://tex.z-dn.net/?f=R%20%3D%203.25%20%5Cmu%20ohms)
Distance of the wire from the center of the coil, d = 20 cm = 0.2 m
The magnetic field, B₁, when the wire is at a distance, d, from the center of the coil.
![B_{1} = \frac{4\pi* 10^{-7} *3.45 }{2\pi *0.2}\\B_{1} =0.00000345 T](https://tex.z-dn.net/?f=B_%7B1%7D%20%3D%20%5Cfrac%7B4%5Cpi%2A%2010%5E%7B-7%7D%20%20%2A3.45%20%7D%7B2%5Cpi%20%2A0.2%7D%5C%5CB_%7B1%7D%20%3D0.00000345%20T)
Magnetic field B₂ when the wire is at a distance, 2d from the center of the coil
![B_{2} = \frac{\mu_{0}I }{2\pi(2d)) } \\B_{2} = \frac{\mu_{0}I }{4\pi d } \\](https://tex.z-dn.net/?f=B_%7B2%7D%20%3D%20%5Cfrac%7B%5Cmu_%7B0%7DI%20%7D%7B2%5Cpi%282d%29%29%20%7D%20%5C%5CB_%7B2%7D%20%3D%20%5Cfrac%7B%5Cmu_%7B0%7DI%20%7D%7B4%5Cpi%20d%20%7D%20%5C%5C)
![B_{2} = \frac{4\pi* 10^{-7} *3.45 }{2\pi *2*0.2}\\B_{2} = 0.000001725 T](https://tex.z-dn.net/?f=B_%7B2%7D%20%3D%20%5Cfrac%7B4%5Cpi%2A%2010%5E%7B-7%7D%20%20%2A3.45%20%7D%7B2%5Cpi%20%2A2%2A0.2%7D%5C%5CB_%7B2%7D%20%3D%200.000001725%20T)
Change in the magnetic field, ΔB = B₂ - B₁ = 0.00001725 - 0.0000345
ΔB = -0.000001725
Induced current, ![I = \frac{E}{R}](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BE%7D%7BR%7D)
E = -N (Δ∅)/Δt
Δ∅ = A ΔB
Area, A = πr²
diameter, d = 0.0125 m
Radius, r = 0.00625 m
A = π* 0.00625²
A = 0.0001227 m²
Δ∅ = -0.000001725 * 0.0001227
Δ∅ = -211.6575 * 10⁻¹²
E = -N (Δ∅)/Δt
![E = -5\frac{-211.6575 * 10^{-12} }{4.70} \\E = 225.17 * 10^{-12} V](https://tex.z-dn.net/?f=E%20%3D%20-5%5Cfrac%7B-211.6575%20%2A%2010%5E%7B-12%7D%20%7D%7B4.70%7D%20%5C%5CE%20%3D%20225.17%20%2A%2010%5E%7B-12%7D%20V)
Resistance, R = 3.25 μ ohms = 3.25 * 10⁻⁶ ohms
I = E/R
![I = \frac{225.17 * 10^{-12} }{3.25 * 10^{-6} }](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7B225.17%20%2A%2010%5E%7B-12%7D%20%7D%7B3.25%20%2A%2010%5E%7B-6%7D%20%7D)
I = 0.0000693 A
I = 69 .3 * 10⁻⁶A
I = 69.3 μA