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statuscvo [17]
3 years ago
13

Juan, a biologist, notices that a particular group of hummingbirds leaves during the colder winter months and returns during the

warmer spring months. Juan hypothesizes that the birds fly south to locations with warmer weather and blooming flowers during the winter months. Which procedure should Juan use to test his hypothesis?​
Physics
1 answer:
Katena32 [7]3 years ago
4 0

Answer:

C. Tag the hummingbirds with transmitters and track their movement.

Explanation:

Hypothesis refers to the conclusion of the analysis found on the grounds of certain observations. The hypothesis is further tested and verified by performing certain experiments. In the given excerpt, Juan hypothesizes that certain group of hummingbirds fly to certain locations depending upon the season. To test the hypothesis, Juan can experiment with finding and tracking the hummingbirds and the direction in which they fly. Tagging the hummingbirds with transmitters and tracking their movement would help Juan concluding about the hypothesis.

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Electromagnetic waves, which include light, consist of vibrations of electric and magnetic fields, and they all travel at the sp
Alekssandra [29.7K]

Answer:

2.92682 m

1.5\times 10^{18}\ Hz

250000000000 Hz

2.88462\times 10^{-8}\ m

0.21126 m

0.12244 m

Explanation:

c = Speed of light = 3\times 10^8\ m/s

\lambda = Wavelength

f = Frequency

Wavelength is given by

\lambda=\dfrac{c}{f}\\\Rightarrow \lambda=\dfrac{3\times 10^8}{102.5\times 10^6}\\\Rightarrow \lambda=2.92682\ m

The wavelength is 2.92682 m

Frequency is given by

f=\dfrac{c}{\lambda}\\\Rightarrow f=\dfrac{3\times 10^8}{0.2\times 10^{-9}}\\\Rightarrow f=1.5\times 10^{18}\ Hz

The frequency is 1.5\times 10^{18}\ Hz

f=\dfrac{c}{\lambda}\\\Rightarrow f=\dfrac{3\times 10^8}{1.2\times 10^{-3}}\\\Rightarrow f=250000000000\ Hz

The frequency is 250000000000 Hz

\lambda=\dfrac{c}{f}\\\Rightarrow \lambda=\dfrac{3\times 10^8}{1.04\times 10^{16}}\\\Rightarrow \lambda=2.88462\times 10^{-8}\ m

The wavelength is 2.88462\times 10^{-8}\ m

\lambda=\dfrac{c}{f}\\\Rightarrow \lambda=\dfrac{3\times 10^8}{1.42\times 10^{9}}\\\Rightarrow \lambda=0.21126\ m

The wavelength is 0.21126 m

\lambda=\dfrac{c}{f}\\\Rightarrow \lambda=\dfrac{3\times 10^8}{2.45\times 10^9}\\\Rightarrow \lambda=0.12244\ m

The wavelength is 0.12244 m

8 0
3 years ago
2. The force between charges is 7 N. The distance between the charges is 4 x 10-6 m. If one of the charges is 2 x 10-8 C, what i
g100num [7]

Answer:

2) 6.22 × 10^-13

3) 4.56 × 10^-4

Explanation:

4 0
3 years ago
A 62.0-kg skier is moving at 6.30 m/s on a frictionless, horizontal, snow-covered plateau when she encounters a rough patch 4.90
Klio2033 [76]
Here are the missing questions:
(a) How fast is the skier moving when she gets to the bottom of the hill?
(b) How much internal energy was generated in crossing the rough patch?
Part A
The initial kinetic energy of the skier is:
E_{k0}=m\frac{v_0^2}{2}
Part of this energy is then used to do work against the force of friction. Force of friction on the horizontal surface can be calculated using following formula:
F_f=mg\mu
The work is simply the force times the length:
W_f=F_f\cdot L=mg\mu L
So when the skier passes over the rough patch its energy is:
E=E_{k0}-W_f
When the skier is going down the skill gravitational potential energy is transformed into the kinetic energy:
E_p=E_{k1}\\ mgh=E_{k1}
So the final energy of the skier is:
E_f=E_{k0}-W_f+E_{k1}\\ E_f=m\frac{v_0^2}{2}-mg\mu L+mgh=1856.86$J
This energy is the kinetic energy of the skier:
E_f=m\frac{v_f^2}{2}\\ v_f=\sqrt{\frac{2E_f}{m}}=7.74\frac{m}{s}
Part B
We know that skier lost some of its kinetic energy when crossing over the rough patch. This energy is equal to the work done by the skier against the force of friction.
E_{int}=W_f\\
E_{int}=mg\mu L=894.1$J

4 0
4 years ago
An object experiences an acceleration of 8.5 m/s^2 over a distance of 300 m. After that acceleration it has a velocity of 400 m/
Snezhnost [94]

Answer:

393.6m/s

Explanation:

Given parameters:

Acceleration  = 8.5m/s²

Distance  = 300m

Final velocity  = 400m/s

Unknown:

Initial velocity  = ?

Solution:

To solve this problem, we use the expression below;

             v² = u²  + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

      So;

               v²  - 2as = u²

        u²   = v²   - 2as

        u²  = 400²   - (2 x 8.5 x 300)  

         u   = 393.6m/s

7 0
3 years ago
Read 2 more answers
A 4800 Watt heater is supposed to be plugged into a 120 volt outlet to work correctly. If the heater was plugged into a 90 volt
dedylja [7]

Answer:

3600

Explanation:

90 of 120 is 3/4 so 4800 - 1200 is 3600.

3 0
3 years ago
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