Point the muzzle in a safe direction.
Answer:
Explanation:
For entry of light into tube of unknown refractive index
sin ( 90 - 25 ) / sinr = μ , μ is the refractive index of the tube , r is angle of refraction in the medium of tube
r = 90 - C where C is critical angle between μ and body medium in which tube will be inserted.
sin ( 90 - 25 ) / sin( 90 - C) = μ
sin65 / cos C = μ
sinC = 1.33 / μ , where 1.33 is the refractive index of body liquid.
From these equations
sin65 / cos C = 1.33 / sinC
TanC = 1.33 / sin65
TanC = 1.33 / .9063
TanC = 1.4675
C= 56°
sinC = 1.33 / μ
μ = 1.33 / sinC
= 1.33 / sin56
= 1.33 / .829
μ = 1.6 Ans
Acceleration occurs when velocities change.velocity changes either because the speed changes or the direction change.
First overtone of open organ pipe is given as
![f_{1o} = \frac{v}{L_1 + 2e}](https://tex.z-dn.net/?f=f_%7B1o%7D%20%3D%20%5Cfrac%7Bv%7D%7BL_1%20%2B%202e%7D)
first overtone of closed organ pipe is given as
![f_{1c} = \frac{3v}{4(L_2 + e)}](https://tex.z-dn.net/?f=f_%7B1c%7D%20%3D%20%5Cfrac%7B3v%7D%7B4%28L_2%20%2B%20e%29%7D)
now they are in unison so we will have
![\frac{v}{L_1 + 2e} = \frac{3v}{4(L_2 + e)}](https://tex.z-dn.net/?f=%5Cfrac%7Bv%7D%7BL_1%20%2B%202e%7D%20%3D%20%5Cfrac%7B3v%7D%7B4%28L_2%20%2B%20e%29%7D)
![\frac{1}{30 + 2e} = \frac{3}{4(23 + e)}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B30%20%2B%202e%7D%20%3D%20%5Cfrac%7B3%7D%7B4%2823%20%2B%20e%29%7D)
![90 + 6e = 92 + 4e](https://tex.z-dn.net/?f=90%20%2B%206e%20%3D%2092%20%2B%204e%20)
![e = 1 cm](https://tex.z-dn.net/?f=e%20%3D%201%20cm)
so end correction of both pipes is e = 1 cm