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Reika [66]
3 years ago
11

In California the pacific plate slides past the North American plate. If the pacific plate is moving at a speed of 5 centimeters

per year how long will it take for the plate to travel 100 meters
Physics
1 answer:
RUDIKE [14]3 years ago
5 0

Answer:

2000years

Explanation:

We will either convert the distance to centimeters or speed to meters/second.

Converting distance to centimeters: 100 meters= 100*100centimeters =10000centimeters.

time=distance/speed

t=10000/5=2000 years

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Answer: 9.9 seconds

Explanation:

that's just how long it takes

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What happens when you dip open bottle in bucket full of water?why​?<br>chapter=pressure​
Degger [83]

Answer: It goes inside filling most of it .

Explanation: This happens because the bottle is empty and the bucket is full of water.

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3 years ago
g A lighter ball A with momentum PA=5.0 kg∙m/s in positive x-direction approaches a heavier ball B at rest before the collision.
Svet_ta [14]

Answer:

7kgm/s

Explanation:

Using the law of conservation of momentum which states that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision.

Let P1A and P1B be the initial momentum of the bodies A and B respectively

Let P2A and P2B be the final momentum of the bodies A and B respectively after collision.

Based on the law:

P1A+P2A = P1B + P2B

Given P1A = 5kgm/s

P2A = 0kgm/s(ball B at rest before collision)

P2A = -2.0kgm/s (negative because it moves in the negative x direction)

P2B = ?

Substituting the values in the equation gives;

5+0 = -2+P2B

5+2 = P2B

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3 0
3 years ago
The figure shows a 100-kg block being released from rest from a height of 1.0 m. It then takes it 0.90 s to reach the floor. Wha
Anna007 [38]

Answer:

The mass of the another block is 60 kg.

Explanation:

Given that,

Mass of block M= 100 kg

Height = 1.0 m

Time = 0.90 s

Let the mass of the other block is m.

We need to calculate the acceleration of each block

Using equation of motion

s=ut+\dfrac{1}{2}at^2

Put the value into the formula

1.0=0+\dfrac{1}{2}\times a\times(0.90)^2

a=\dfrac{2\times1.0}{(0.90)^2}

a=2.46\ m/s^2

We need to calculate the mass of the other block

Using newton's second law

The net force of the block M

Ma=Mg-T

T=Mg-Ma....(I)

The net force of the block m

ma=T-mg

Put the value of T from equation (I)

ma=Mg-Ma-mg

m(a+g)=M(g-a)

m=\dfrac{M(g-a)}{(a+g)}

Put the value into the formula

m=\dfrac{100(9.8-2.46)}{2.46+9.8}

m=59.8\ \approx60\ kg

Hence, The mass of the another block is 60 kg.

8 0
3 years ago
A block of stone measures 15cm x 15cm x 20 cm.What is the total surface area of the stone
Sidana [21]

This should help look at the pictures?

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