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Natalija [7]
3 years ago
15

Find the sum of 29,the product of 2 and 9 and the difference between 2 and 9​

Mathematics
1 answer:
g100num [7]3 years ago
7 0

Step-by-step explanation:

Sum means adding of numbers

Product means multiplying the numbers

Difference means minus two numbers

First number is 2 and other number is 9.

Sum of 2 and 9 = 2+9 = 11

Product of 2 and 9 = 2×9 = 18

Difference between 2 and 9 = 9-2 = 7

Hence, this is the required solution.

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Find the sum of the first 12 terms of the geometric sequence - 2,6,-18,54,-162....​
nekit [7.7K]

Answer:

Sure, the common difference is -3, but like you have to multiple it and stuff, so it goes like this: -2,6,-18,54,-162,486,-1458,4374,-13122,39366,-118,098,354294.

So then, add all of the 12 terms I stated, and that will equal to 265,720

Therefore, the sum of the first 12 terms of that geometric sequence is 265,720.

Step-by-step explanation:

6 0
3 years ago
What is 2/6 x 3/9 i need help
Ira Lisetskai [31]

Answer:1/9

Step-by-step explanation:

Simplified:

1/3 x 1/3

1/9

3 0
3 years ago
Read 2 more answers
Help please quick!!!!15 points!! What is the area of this parallelogram
Stells [14]

Answer:

132

Step-by-step explanation:

area of a parallelogram is b*h

(6+5)(12)=132

3 0
3 years ago
You invest $9000 with a 6% interest rate compounded semiannually. After 9 yrs, how much money is in your account?
astraxan [27]
\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$9000\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\

t=years\to &9
\end{cases}
\\\\\\
A=9000\left(1+\frac{0.06}{2}\right)^{2\cdot 9}
7 0
3 years ago
Write an equation of the line passing through the point (3, -1) and parallel to the line y=2/3x - 5. Show work
alex41 [277]

Answer:

The answer is: y = 2/3x - 3

Step-by-step explanation:

Given point: (3, -1)

Given equation: y = 2/3x - 5, which is in the form y = mx + b where m is the slope and b is the y intercept.

Parallel lines have the same slope. Use the point slope form of the equation with the point (3, -1) and substitute:

y - y1 = m(x - x1)

y - (-1) = 2/3(x - 3)

y + 1 = 2/3x - 6/3

y + 1 = 2/3x - 2

y = 2/3x - 3

Proof:

f(3) = 2/3(3) - 3

= 6/3 - 3

= 2 - 3

= -1, giving the point (3, -1)

Hope this helps! Have an Awesome Day!!  :-)

6 0
3 years ago
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