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UkoKoshka [18]
3 years ago
8

Can someone help me with this

Biology
1 answer:
alexira [117]3 years ago
8 0
Was encountered at this station in 1952 egg resume with development with diploid complement of chromosome.
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Part C If you were the head of an ocean conservation program, what concerns would you have about implementing this method of cor
timurjin [86]

Answer:

It causes no pollution.

Explanation:

The first concern about implementing the method used for coral regeneration is that it causes no water pollution in order to protect the other aquatic animals from the harmful effect of the method used for restoration. If the harmful effect of coral regeneration is higher and disturbing so it must be avoided in order to save other organisms but if there is no harmful effect of the method used for coral regeneration so it must be used.

6 0
3 years ago
The picture above shows a microscopic view of an animal cell. Which of the following is an observation that can be made about th
SOVA2 [1]

Answer:

Awnser

Explanation:

The Awnser is C _________________

6 0
2 years ago
Does anyone have answers i will give brailiest for the first person who answers Lesson 11: The Nature of Life Unit Test
Drupady [299]
I don't know if this will help you or not but here you go.

https://quizlet.com/225903868/lesson-11-the-nature-of-life-unit-test-biology-a-unit-1-the-nature-of-life-flash-cards/
6 0
3 years ago
TRUE OR FALSE?
Kamila [148]
I believe this would be true
7 0
3 years ago
Read 2 more answers
There are 100 cats in a population that follows hardy-weinberg conditions. 4 cats display a recessive white coat color. how many
mr Goodwill [35]

We know that Hardy-Weinberg conditions include the following equations:


p^{2}+2pq+ q^{2}=1


where p+q=1


And where p = dominant, and q = recessive; this means that p^{2} is equal to the homozygous dominant, 2pq is the heterozygous, and q^{2} is the homozygous recessive .


So we have 100 total cats, with 4 having the recessive white coat color. That means we have a ratio of \frac{4}{100} or 0.04. Let that equal our q^{2} value.


So when we solve for q, we get:


q^{2}=0.04

q=\sqrt{0.04} =0.2


Now that we have our q value, we can use the other equation to find p:


p+q=1


p+0.2=1


p=0.8


So then we can solve for our heterozygous population:


2pq=2(0.8)(0.2)=0.32


This is the ratio of the population. So we then multiply this number by 100 to get the number of cats that are heterozygous:


0.32*100=32cats


So now we know that there are 32 heterozygous cats in the population.

8 0
3 years ago
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