


Let the marked prize of the TV be x .

We have SP = MP - Discount



<em>Hence </em><em>,</em><em> </em><em>T</em><em>he </em><em>marked</em><em> </em><em>prize</em><em> </em><em>of </em><em>the </em><em>TV </em><em>is </em><em>₹</em><em>2</em><em>0</em><em>,</em><em>2</em><em>5</em><em>0</em><em> </em><em>.</em>
<em>Hope </em><em>it </em><em>helps </em><em>~</em><em> </em>
We must fine the conversion for this, so we have to divide $270 by 200€ to get 1.35 Dollars for every Euro..
Now we multiply 300 by 1.35 to get 405 dollars
Volume of water in the tank:

Differentiate both sides with respect to time <em>t</em> :

<em>V</em> changes at a rate of 2000 cc/min (cubic cm per minute); use this to solve for d<em>h</em>/d<em>t</em> :


(The question asks how the height changes at the exact moment the height is 50 cm, but this info is a red herring because the rate of change is constant.)
Answer:
C ) 40w + 300 > 7--
Step-by-step explanation:
Since he starts off with 300 cards, the equation must have +300 units. As he purchases 40 each week, the rate of change is 40w. Since his goal is over 700, look for >700.
Therefore 40w + 300 > 700
a.
×
A
b.
×
A
c.
A
The LED which would glow brightest is LED C with the greatest current and voltage
The LED which would be the most dim is LED B with low voltage and consequently low current.
<h3>How to determine the current</h3>
The formula for finding current
I = V/R
Where v = voltage
R = resistance
A. V = 12V
R = 4. 7 + 15 = 19. 7 kΩ = 19700 Ω in series

×
A
B. V = 9V
R = 4. 7 + 1 = 4. 7 kΩ = 4700Ω in series

×
A
C. V= 12V
1/R =
=
× 
R =
= 310. 56 Ω

A
It is important to note that the brightness of a bulb depends on both current and voltage depending on whether the bulb it is in parallel or series.
The LED which would glow brightest is LED C with the greatest current and voltage
The LED which would be the most dim is LED B with low voltage and consequently low current.
Learn more about Ohms law here:
brainly.com/question/14296509
#SPJ1