You should just transfer -16 to the other side so you gonna have : c = 41 + 16 so c = 57 :))
i hope this be helpful
have nice day
Let the numbers be x and y.
by the first statement of the question, we get , x + y = 30.,,..(1)
by the second satement, we get , x = y+ y => x=2y... (2)
from equation (2), let us put the value of x in equation (1),
x + y = 30
=> 2y + y = 30
=> 3y = 30
=> y =30/3
=> y = 10
and x=2y => x = 2*10 = 20
in short, the numbers are 10 and 20
Answer: 13, 14
Step-by-step explanation:
I counted
Answer:
\frac{276}{5}-8x)
Step-by-step explanation:
We are given with
H(x)=1/3x3/3 3x2+9x-2
And
M(x)=13 3/5x+6x3-2x2-4x
And asked to determine
[h(x) +m(x)]-[h(x)-m(x)]
Opening the second parenthesis
h(x) +m(x)-h(x)+m(x)
As we subtracted the second bracket, the sign get reversed.
As h(x) has opposite signs , they get cancelled
h(x) +m(x)-h(x)+m(x)
=2m(x)
=2(13\tfrac{3}/{5}x+6x3-2x2-4x)
=2(\frac{13 \times 5 + 3}{5}+18-4-4x)
=2(\frac{68}{5}+14-4x)
=2(\frac{68+70}{5}-4x)
=2(\frac{138}{5}-4x)
=\frac{276}{5}-8x)