So what this is is
many words
assuming year 0 is 2017
so compound first thing till 2020, take out 30000
the remaining is copmpounded til 2022, take out 50000
remaining is compounded for 1 more year and that is equal to 80000
so from 2017 to 2020, that is 5 years
from 2020 to 2022 is 2 years
from 2022 to 2023 is 1 year
work backwards
A=P(r+1)^t
last one
A=80000
P=?
r=0.08
t=1 year
80000=P(1.08)^1
divide both sides by 1.08
I would leave in fraction
20000000/27=P
now that is the remaining after paying 50000, after 2 years of compounding
so
50000+(2000000/27)=P(1.08)^2
solve using math
about
106374=P
now reverse back
5 years
paid 30000
30000+106374=P(1.08)^5
solve using math
92813.526=P
round
$92813.53
put $92813.53 in the fund
a.
This is the geometric sequence: a1 = 1.5 m = 150
cm, r = 0.74
The formula now is an = a1 x r ^ n-1
Just substitute a1 = 150 cm and r = 0.74
an = 150 x (0.74) ^ n – 1
b.
The second part is:
A6 = 150 x 0.74 ^ 6-1
= 150 x 0.74 ^5
= 150 x 0.221906624
= 33.28509936 cm
Answer:
1 3 ...................rotate 3 and it is the same as 1
