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mixas84 [53]
3 years ago
7

What is the area of this circle that is 98cm in diameter

Mathematics
1 answer:
Romashka [77]3 years ago
8 0
111jjiYkzkhxkhxkgzgkzkgzkgxkgzkyktKtzykzlyzykzkyzkyzkyzykzk
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I need help with this logic puzzle,
natka813 [3]
I cannot reach a meaningful solution from the given information. To prove that S was always true, you would have to prove that N was always false. To prove that N was always false you would have to prove that L was always false. For the statement (L ^ T) -> K to be true, you only need K to be true, so L can be either true or false.
Therefore, because of the aforementioned knowledge, I do not believe that you can prove S to be true. 
3 0
4 years ago
Given the following functions f(x) and g(x), solve (f + g)(3) and select the correct answer below:
kati45 [8]
(f+g)(3) = f(3) + g(3) = 6(3) + 3 + 3 -7 = 18 +6 -7 = 17.

Answer: 17
8 0
3 years ago
Read 2 more answers
Which expressions are equivalent to this expression?
Lyrx [107]

Answer:

Option B

Option C

Option D

All of these are correct

Step-by-step explanation:

Option B is correct because:

2x + 1 + 2x + 3 = 4x + 4

=> 4x + 4 = 4x + 4

Option C is correct because:

x + 3x + 4 = 4x + 4

=> 4x + 4  = 4x + 4

Option D is correct because:

2(2x + 2) = 4x + 4

=> 4x + 4 = 4x + 4

Option A is incorrect because:

4(x + 4) = 4x + 4

=> 4x + 16 ≠ 4x + 4

7 0
3 years ago
If the population has gone up 20,000 in 6yr what percent is that
Sedaia [141]
I think it is 3333% #I guessed
6 0
4 years ago
A fireplace arch is to be constructed in the form of a semiellipse. The opening is to have a height of 3 feet at the center and
USPshnik [31]

Answer:

Step-by-step explanation:

Given

Fireplace is in the form of semi-ellipse  with height of 3 ft from center

Length of base=8 ft

if the arch is in the form of ellipse then it can be considered as horizontal ellipse with 2 a and 2 b be length of major and minor axis

2 a =8

a=4 ft

If contractor cover the whole base

then total length of string=2a =8 ft

(b)String should be nailed at focus

focus of ellipse is a e

where e=eccentricity

e=\sqrt{1-(\frac{b}{a})^2}

e=\sqrt{1-(\frac{3}{4})^2}=\frac{\sqrt{7}}{4}

Focus =ae =\sqrt{7}

Thus string should be nailed at 2.64 m from center

8 0
3 years ago
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