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kramer
3 years ago
11

Write the equation of the line in point-slope form that passes through (5, -1) and has a slope of 2/3

Mathematics
1 answer:
kolezko [41]3 years ago
5 0

Answer:

y-(-1)=2/3(x-5)

Step-by-step explanation:

Point slope form is

y-y_1=m(x-x_1) where m is the slope, x_1 is the x coordinate of a point that the line passes through, and y_1 is the y coordinate of a point the line passes through.

Substituting, we get

y-(-1)=2/3(x-5)

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Answer:

(5,2,2)

Step-by-step explanation:

-3x+4y+2z = -3

2x-4y-z=0

y = 3x-13


Multiply the second equation by 2

2*(2x-4y-z)=0*2

4x -8y -2z =0

Add this to the first equation to eliminate z

-3x+4y+2z = -3

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Take the third equation and substitute it in for y

x - 4(3x-13) = -3

Distribute the 4

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-11x = -55

Divide by -11

-11x/-11 = -55/-11

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y =3x-13

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10-8 -z=0

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Add z to each side

2-z+z= 0+z

2=z

x=5, y=2, z=2

(5,2,2)

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