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4 years ago

Factor completely

Mathematics

2 answers:

svet-max [94.6K]4 years ago

8 0

Answer:

B.) 2(5x-4)(x+1)

Step-by-step explanation:

10x^2+2x-8

= 2(5x^2 + x - 4)

= 2(5x^2 + 5x - 4x - 4)

= 2[5x(x + 1) - 4(x + 1)]

= 2(5x-4)(x+1)

Vera_Pavlovna [14]4 years ago

5 0

Answer:

B.) 2(5x - 4)(x + 1).

Step-by-step explanation:

10x^2+2x-8

First divide by the common factor 2:

= 2(5x^2 + x - 4)

Now we factor the expression in the parentheses using the 'ac' method.

5 * -4 = -20 so to get the + x in the middle we need 5x - 4x:

= 2 ( 5x^2 + 5x - 4x - 4)

= 2[ 5x(x + 1) - 4(x + 1)]

= 2(5x - 4)(x + 1) (answer).

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