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3 years ago

12

I'm in algebra 1 please help i'm lost

2 answers:

Delicious77 [7]3 years ago

6 0

3(x^2 - 1) - (x^2 -7x + 10)
Distribute the 3 in the first parenthesis and the negative in the second parenthesis. Then combine like terms.
3x^2 -3 -x^2 + 7x -10
2x^2 + 7x -13
# 2 is the answers

Likurg_2 [28]3 years ago

5 0

3x2 -3 -x2 +7x -10 =2x2 +7x -13

so thats (2)

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What is the slope of the line graphed below??

Burka [1]

We can use the points (1, 2) and (3, -4) to solve.

Slope formula: y2-y1/x2-x1

= -4-2/3-1

= -6/2

= -3

Hope This helped! Good Luck!

8 0

4 years ago

Nadia has a bag of different colored balloons. Without

Jobisdone [24]

Answer: A.4/25

Step-by-step explanation:

Number of trials that were performed = 50

Number of times a blue balloon was chosen = 22

Number of times a yellow balloon was chosen = 7

Number of times an orange balloon was chosen = 8

Number of times a purple balloon was chosen = 13

The estimated probability of choosing an orange balloon from the bag will be the number of times that an orange balloon was chosen divided by the total number of trials. This will be:

= 8/50

= 4/25

8 0

3 years ago

Read 2 more answers

Match each differential equation to a function which is a solution.

inessss [21]

Answer: 1 - C

2 - E

3 - no answer

4 - B

Step-by-step explanation:

A. $y = 3x+x^2$

$y' = 3 + 2x\\y'' = 2$

Replace in 1:

$y'' + y = 0$

$2 + 3x + x^2 \neq 0$

So, A is not an answer for 1

Replace in 2:

$y' = 3y$

$3+2x = 3(3x + x^2)$

So, A is not an answer for 2

Replace in 3

$2x^2y'' + 3xy'= y$

$2x^2(2) + 3x(3 + 2x) = 4x^2 + 9x + 6x^2 \neq 3x+x^2$

So, A is not an answer for 3

Replace in 4

$y'' + 6y' + 8y = 0$

$2 + 6(3+2x)+8(3x + x^2) = 2+18+12x+24x+8x^2 \neq 0$

So, A is not an answer for 4

B. $y = e^{-4x}$

$y' = -4e^{-4x}$

$y'' = 16e^{-4x}$

Replace in 1

$y'' + y = 0$

$16e^{-4x} -4e^{-4x} = 12e^{-4x} \neq 0$

So, B is not an answer for 1

Replace in 2

$y' = 3y$

$-4e^{-4x} \neq 3e^{-4x}$

So, B is not an answer for 2

Replace in 3

$2x^2y'' + 3xy' = y$

$2x^2(16e^{-4x}) +3x(-4e^{-4x}) \neq e^{-4x}$

So, B is not an answer for 3

Replace in 4

$y'' + 6y' +8y = 0$

$16e^{-4x} + 6(-4e^{-4x}) + 8e^{-4x} = e^{-4x}(16-24+8) = 0$

So, B is an answer for 4

C. $y = sin(x)$

$y' = cos(x)$

$y'' = -sin(x)$

Replace in 1

$y'' + y = 0$

$-sin(x) + sin(x) = 0$

So, C is an answer for 1

We jump to

D. $y = x^{12}$

$y' = 12x^{11}$

$y'' = 132 x^{10}$

Replace in 2

$y' = 3y$

$12x^{11} \neq 3x^{12}$

So, D is not an answer for 2

Replace in 3

$2x^2y'' + 3xy' = y$

$2x^2(132x^{10}) + 3x(12x^{11}) = 300x^{12} \neq x^{12}$

So, D is not an answer for 3

E. $y = 6e^{3x}$

$y' = 18e^{3x}$

$y'' = 54e^{3x}$

Replace in 2

$y' = 3y$

$18e^{3x} = 3(6e^{3x}) = 18e^{3x}$

So, E is an answer for 2

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3 years ago

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Answer:

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3 years ago

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lys-0071 [83]

Answer:

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3 years ago