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3 years ago

I'm in algebra 1 please help i'm lost

Mathematics

2 answers:

Delicious77 [7]3 years ago

6 0

3(x^2 - 1) - (x^2 -7x + 10)
Distribute the 3 in the first parenthesis and the negative in the second parenthesis. Then combine like terms.
3x^2 -3 -x^2 + 7x -10
2x^2 + 7x -13
# 2 is the answers

Likurg_2 [28]3 years ago

5 0

3x2 -3 -x2 +7x -10 =2x2 +7x -13

so thats (2)

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A box has a volume of 192 cubic inches, a length that is twice as long as its width, and a height that is 2 inches greater than

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Therefore the dimension of the cuboid is 8 inches×4 inches ×6 inches.

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A cuboid contains 8 vertices.
A cuboid contains 12 edges .
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The dimension of a cuboid is written as length×breadth×height.

The volume is( length×breadth×height) cubic units

Given that the volume of the box is 192 cubic inches.

Let x inches be the width of the cuboid.

Since the length is twice as long as its width.

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Again height is 2 inches longer than width.

Then height = (x+2) inches.

Therefore the volume of the cuboid is

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$=[2x^2(x+2)]$ cubic inches

$=(2x^3+4x^2)$ cubic inches

According to the problem,

$2x^3+4x^2=192$

$\Rightarrow 2x^3+4x^2-192=0$

$\Rightarrow 2(x^3+2x^2-96)=0$

$\Rightarrow (x^3+2x^2-96)=0$

$\Rightarrow x^3-4x^2+6x^2-24x+24x-96=0$

$\Rightarrow x^2(x-4) +6x(x-4)+24(x-4)=0$

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Therefore x=4

Since the all zeros of x²+6x+24 =0 is negative.

Therefore breadth = 4 inches

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and height = (4+2)inches = 6 inches.

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