Hi there!
We can use right-triangle trigonometry to solve.
We are given the HYPOTENUSE and ADJACENT sides, so we must use cosine in this instance.
cosθ = Adjacent/Hypotenuse
We can plug in what is given:
cos(28) = A/17
Solve for 'A':
17cos(28) = <u>15.01 ft</u>
Answer:
In the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28
Step-by-step explanation:
Given equation is -14(3a+6)=12(6-4a)+12
To simplify the given equation:
-14(3a+6)=12(6-4a)+12
Taking all terms to one side
-14(3a+6)-12(6-4a)-12=0
-[14(3a+6)+12(6-4a)+12]=0
Now dividing by negative sign on the above equation we get
14(3a+6)+12(6-4a)+12=0 (using distributive property)
42a+84+72-48a+12=0 ( adding the like terms )
-6a+168=0
-6a=-168
6a=168
Therefore a=28
Therefore in the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28
We need to determine the radius and diameter of the circle. If the area of the circle is 10 pi in^2, then, according to the formula for the area of a circle,
A = 10 pi in^2 = pi*r^2. Thus, 10 in^2 = r^2, and r = radius of circle = sqrt(10) in.
Thus, the diam. of the circle is 2sqrt(10) in. This diam. has the same length as does the hypotenuse of one of the triangles making up the square.
Thus, [ 2*sqrt(10) ]^2 = x^2 + x^2, where x represents the length of one side of the square. So, 4(10) in^2 = 2x^2. Then:
40 in^2 = 2x^2, or 20 in^2 = x^2, and so the length x of one side of the square is sqrt(20). The area of the square is the square of this result:
Area of the square = x^2 = [ sqrt(20) ]^2 = 20 in^2 (answer). Compare that to the 10 pi sq in area of the circle (31.42 in^2).
Answer:
1/6
Step-by-step explanation:
The probability of <em>only</em> a heads on a coin is 1/2, and the probability of <em>only</em> a 3 on a die is 1/6. Multiply them together, and you get 1/6.
Setup is
y = k/x
8 = k/3
k = 24
Now use 6 for y
6 = 24/x
x = 24/6 = 4 or A
