The two lines intersect at the point (4, 214). This means that the attendance was 214 for both plays on the 4th night.
<span>B. The attendance was the same on day 4. The attendance was 214 at both plays that day.</span>
Answer: 4xy+6x+2x^2
Step-by-step explanation:
4xy-2x+2x^2+8x
we can combine the terms that only have an x (Ax for any number A)
in this case that's -2x and 8x
-2x+8x=6x
the other things can't be combined
thus you end up with
4xy+6x+2x^2
-2x³ + 3 = -x³ - x² + x + 1
Add x³ to both sides, and subtract 3 from both sides.
-2x³ + x³ = -x² + x + 1 - 3
Add like terms.
-x³ = -x²+ x - 2
Move all of the (X's) to both sides, by adding x² to both sides, and subtracting x form both sides.
-x³ + x² - x = -2
~Hope I helped!~
Answer:
1 is b and 2 is a
Step-by-step explanation:
Answer:
y-determinant = 2
Step-by-step explanation:
Given the following system of equation:
Let's represent it using a matrix:
![\left[\begin{array}{ccc}1&2\\1&-3\end{array}\right] = \left[\begin{array}{ccc}5\\7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%5C%5C1%26-3%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C7%5Cend%7Barray%7D%5Cright%5D)
The y‐numerator determinant is formed by taking the constant terms from the system and placing them in the y‐coefficient positions and retaining the x‐coefficients. Then:
![\left[\begin{array}{ccc}1&5\\1&7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%265%5C%5C1%267%5Cend%7Barray%7D%5Cright%5D%20)
y-determinant = (1)(7) - (5)(1) = 2.
Therefore, the y-determinant = 2
