Something is reproducing.
Answer:
Between 2.0 s and 4.0 s (B and C)
Between 5.0 s and 8.0 s (D and E)
Between 10.0 s and 11.0 s (F and G)
Explanation:
The graph shown in the figure is a velocity-time graph, which means that:
- On the x-axis, the time is plotted
- On the y-axis, the velocity is plotted
Therefore, this means that the object is not moving when the line is horizontal (because at that moment, the velocity is constant, so the object is not moving). This occurs in the following intervals:
Between 2.0 s and 4.0 s (B and C)
Between 5.0 s and 8.0 s (D and E)
Between 10.0 s and 11.0 s (F and G)
From the graph, it would be possible to infer additional information. In particular:
- The area under the graph represents the total distance covered by the object
- The slope of the graph represents the acceleration of the object
Since in an electromagnetic wave the electric and magnetic fields are perpendicular to each other and perpendicular to the direction of motion, the electric field has to point in the z direction.
Answer:768.75N
Explanation:
mass=62.5kg
acceleration=12.3m/s^2
Force=mass x acceleration
Force=62.5 x 12.3
Force=768.75N
Answer: a) 16Hz, 3m b) 48Hz, 1mc) 80Hz, 0.6m
Explanation:
a) Fundamental frequency in string is represented as Fo = V/2L where;
Fo is the fundamental frequency
V is the speed of the transverse wave = 48m/s
L is the length of the wire. = 1.50m
Substituting this values in the formula given we have;
Fo = 48/2(1.5)
Fo = 48/3
Fo = 16Hz
The fundamental tone is therefore 16Hz
Using v =f¶
Where f is the frequency and ¶ is the wavelength, the wavelength of the fundamental note will be;
¶ = v/fo
¶ = 48/16 = 3m
b) Overtones or harmonics is the multiple integral of the fundamental frequency. The multiples are I'm arithmetical progression.
First overtone f1 = 2fo
Second overtone f2 = 3fo etc.
Since fo = 16Hz
Second overtone f2 = 3×16 = 48Hz
¶ = v/f2 = 48/48
¶ = 1m
c) Fourth harmonic or overtone will be f4 = 5fo
F4 = 5×16 = 80Hz
The fourth harmonic is therefore 80Hz
¶ = v/f4 = 48/80
¶ = 0.6m