We are aware that weight is the product of applied gravitational force and mass. W = MG thus, where W represents the weight, M the mass, and G the gravitational force. As a result, it might also mean that "an object's weight is directly proportionate to its mass."
<h3>What is mass?</h3>
- Mass is a physical body's total amount of matter.
- It also serves as a gauge for the body's inertia, or resistance to acceleration (change in velocity) in the presence of a net force.
- The strength of an object's gravitational pull to other bodies is also influenced by its mass.
- The kilogram is the primary mass unit in the SI (kg).
- Even though weight is frequently measured using a spring scale rather than a balancing scale and directly compared with known masses, mass is not the same as weight in physics.
<h3>What is weight?</h3>
- The force exerted on an object by gravity is known as the weight of the object in science and engineering.
- Weight is sometimes described as a vector quantity, or the gravitational force exerted on the object, in some common textbooks.
- Others define weight as a scalar quantity, the gravitational force's strength.
- Others define it as the strength of the force applied to a body as a result of systems designed to resist the effects of gravity; the weight is the amount that is determined, for instance, by a spring scale.
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Answer:
C) Mass
Explanation:
The mass of an object divided by its volume equals the density.
Hope this helps!
Answer:
Explanation:
Unknown fork frequency is either
335 + 5.3 = 340.3 Hz
or
335 - 5.3 = 329.7 Hz
After we modify the known fork, the unknown fork frequency equation becomes either
(335 - x) + 8 = 340.3
(335 - x) = 332.3
x = 2.7 Hz
or
(335 - x) + 8 = 329.7
(335 - x) = 321.7
x = 13.3 Hz
IF the unknown fork frequency was 340.3 Hz,
THEN the 335 Hz fork was detuned to 335 - 2.7 = 332.3 Hz
IF the unknown fork frequency was 329.7 Hz,
THEN the 335 Hz fork was detuned to 335 - 13.3 = 321.7 Hz
Answer:
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Explanation:
Answer:
Explanation:
Initial speed, v = 10 x 10^3 m/s
Mass of the earth, M = 6 x 10^24 kg
Radius of the earth, R = 6.4 x 10^6 m
Maximum from the surface of earth, h = ?
Let m = Mass of the projectile
Solution:
Potential energy at maximum height = ( Potential + Kinetic energy ) at the surface



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