What type of system allows matter and energy to enter and exit?

Helga [31]

Biodiversity refers to the huge variety of all organisms present on the Earth, which conform to the natural world.

The term biodiversity can be considered as a contraction of "biological diversity" and it was developed by Dr. Walter G. Rosen in 1985.

Biodiversity includes all biological kingdoms, i.e., Eukaryota (animals, plants, fungi, and protists), Archaea and Bacteria.

Biodiversity can be defined as different values which can be used to measure the genetic variation and variations at organismal (species) and ecosystem levels.

In conclusion, biodiversity refers to the huge variety of all organisms present on the Earth, which conform to the natural world.

Learn more about biodiversity here:

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7 0

3 years ago

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A small sphere with mass 1.5g hangs by a thread between two parallel vertical plates 5cm apart. The plates are insulating and ha

kondaur [170]

The tralational equilibrium condition allows finding that the electric potential is V = 4.8 10¹¹ V

Given parameter

The mass m = 1.5 g = 1.15 10-3 kg

The charge on the sphere q = 8.9 10-16 C

Plate spacing d = 5 cm = 5.00 10-2 m

To find

The potential difference

Newton's second law states that the force is proportional to the mass and the acceleration of the bodies, in the special case that the acceleration is zero, it establishes the condition for the equilibrium of the bodies

∑ F = 0

Where the bold indicate vector and F is the force

To use this equation we must fix a reference system with respect to which to carry out the decomposition and measurements of the forces; let's fix a system with the horizontal x axis and the vertical y axis, in the attachment I could see a free body diagram.

x- axis

Fe - Tₓ = 0

Fe = Tₓ

y-axis

$T_y$ - W = 0

W = $T_y$

mg = $T_y$

The electric force is

Fe = q E = q V / d

let's use trigonometry to decompose the stress

cos 30 = $T_y$ / T

sin 30 = Tₓ / T

$T_y$ = T cos 30

Tₓ = T sin 30

We substitute

q V / d = T sin 30

mg = T cos 30

It's solve the system of equations

$\frac{q \ V}{d \ m g}$ = tan 30

V = $\frac{d \ mg }{ q}\ tan \ 30$

It's calculate

V = $\frac{5.00 \ 10^{-2} 1.5 \ 10^{-3} \ 9.8}{ 8.9 10^{-16} } \ tan \ 30$

V = 4.768 10¹¹ V

In conclusion, using the equilibrium condition, we could find that the electric potential is V = 4.8 10¹¹ V

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7 0

3 years ago

. Increasing the pressure on a gas __________ the volume the gas occupies. (Points : 1)

skelet666 [1.2K]

A increases plz dont report if wrong just tell me an ill fix it

5 0

3 years ago

Two sites are being considered for wind power generation. In the first site, the wind blows steadily at 7 m/s for 3000 hours per

slavikrds [6]

Answer:

E.year₂ > E.year₁ (Second site is better)

Explanation:

Given data

$V_{1}=7 m/s\\Time_{1}=3000 hours/year\\V_{2}=10m/s\\Time_{2}=1500hours/year$

The power generation is the time rate of kinetic energy which can be calculated as:

Power=ΔKE=m×V²/2

Regarding that m ∝ V.Then

Power ∝ V³ ⇒ Power=constant×V³

Since ρa is constant for both sides and Area is the same as same wind turbine is used

For First site

$Power_{1}=const.V^3\\Power_{1}=const.(7m/s)^3\\Power_{1}=const.343Watt\\$

For second site

$Power_{2}=const.V_{2}^3\\Power_{2}=const.(10m/s)^3\\Power_{2}=const.1000W$

Calculating energy generation per year for each of two sites

E.year=Power×Operation time per year

For First site

E.year₁=Power₁×Operation time₁ per year

$E_{year1}=const.*343W*3000\\E_{year1}=const.1029000(W.hour/year)$

For Second site

E.year₂=Power₂×Operation time₂ per year

$E_{year2}=const.*1000W*1500\\E_{year2}=const.1500000(W.hour/year)$

So

E.year₂ > E.year₁ (Second site is better)

3 0

4 years ago

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An average human weighs about 650 N. If each of two average humans could carry 1.0 C of excess charge, one positive and one nega

bezimeni [28]

Answer:

Distance, r = 3721.04 meters

Explanation:

It is given that,

Charges on both humans, $q_1=q_2=1\ C$

Electric force of attraction between them, F = 650 N

We need to find the separation between two humans. It can be solved using the following formula as :

$F=\dfrac{kq^2}{r^2}$

$r=\sqrt{\dfrac{kq^2}{F}}$

$r=\sqrt{\dfrac{9\times 10^9\times (1)^2}{650}}$

r = 3721.04 meters

So, the distance between the humans is 3721.04 meters. Hence, this is the required solution.

5 0

3 years ago