During which interval is the object not moving

Physics

1 answer:

Bezzdna [24]3 years ago

6 0

Answer:

Between 2.0 s and 4.0 s (B and C)

Between 5.0 s and 8.0 s (D and E)

Between 10.0 s and 11.0 s (F and G)

Explanation:

The graph shown in the figure is a velocity-time graph, which means that:

- On the x-axis, the time is plotted

- On the y-axis, the velocity is plotted

Therefore, this means that the object is not moving when the line is horizontal (because at that moment, the velocity is constant, so the object is not moving). This occurs in the following intervals:

Between 2.0 s and 4.0 s (B and C)

Between 5.0 s and 8.0 s (D and E)

Between 10.0 s and 11.0 s (F and G)

From the graph, it would be possible to infer additional information. In particular:

- The area under the graph represents the total distance covered by the object

- The slope of the graph represents the acceleration of the object

You might be interested in

For any planet, if the planet were to shrink, but have constant mass, what would happen to the value of gravity acceleration (g)

choli [55]

The value of the gravity acceleration on the planet's surface increases

Explanation:

The gravitational acceleration on the surface of a planet is given by:

$g=\frac{GM}{R^2}$

where

G is the gravitational constant

M is the mass of the planet

R is the radius of the planet

In this problem, we are told that the planet shrinks, therefore the new radius is smaller than the original radius:

$R'$

while the mass remains the same:

$M'=M$

Therefore, the new acceleration of gravity is

$g'=\frac{GM}{R'^2}$

We see that the value of g is inversely proportional to the square of the radius of the planet: therefore, since $R'$ , it means that $g'>g$ , so when the planet shrinks, the value of the gravity acceleration on the planet's surface increases.