<img src="https://tex.z-dn.net/?f=%28x%5E2%2B16x%29%5E2%3D17%5E2" id="TexFormula1" title="(x^2+16x)^2=17^2" alt="(x^2+16x)^2=17^

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tresset_1 [31]

3 years ago

2" align="absmiddle" class="latex-formula">
I know the answers. Please show me the correct way to solve this.

Mathematics

1 answer:

OverLord2011 [107]3 years ago

7 0

(x² + 16x)² = 17²

√x² + 16x)² = √17²
(x² + 16x) = (+-)17
1st equation: x²+16x-17 = 0
2nd equation:x²+16x+17 =0
Let's solve these 2 quadratic equation:
1st equation x' =1 & x" = - 17
2nd equation x'= (-8+√47) & x" =(-8-√47)

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