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1 year ago

A square on a coordinate plane is translated 9 units down and 1 unit to the right. Which function rule describes the

Mathematics

1 answer:

Nataly_w [17]1 year ago

6 0

Function rule describes the translation OT_1-9(x, y)

<h3>What is translation?</h3>

A translation is a transformation that occurs when a figure is moved from one location to another location without changing its size, shape or orientation.

A square on a coordinate plane is translated 9 units down and 1 unit to the right.

Let's (x, y) be the coordinate.

where x be the horizontal move and y be the vertical move.

As, it is translated 9 units down and 1 unit right.

then

(x, y) = (x +1, y - 9)

and the translation be

(x, y ) = (x+1, y-9)

Learn more about this concept here:

brainly.com/question/12641072

#SPJ1

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Step-by-step explanation:

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a) The probability that exactly 4 flights are on time is equal to 0.0313

b) The probability that at most 3 flights are on time is equal to 0.0293

c) The probability that at least 8 flights are on time is equal to 0.00586

Step-by-step explanation:

The question posted is incomplete. This is the complete question:

United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the number on-time flights is recorded. Round answers to 3 significant figures.

a) The probability that exactly 4 flights are on time is =

b) The probability that at most 3 flights are on time is =

c)The probability that at least 8 flights are on time is =

<h2>Solution to the problem</h2>

a) Probability that exactly 4 flights are on time

Since there are two possible outcomes, being on time or not being on time, whose probabilities do not change, this is a binomial experiment.

The probability of success (being on time) is p = 0.5.

The probability of fail (note being on time) is q = 1 -p = 1 - 0.5 = 0.5.

You need to find the probability of exactly 4 success on 9 trials: X = 4, n = 9.

The general equation to find the probability of x success in n trials is:

$P(X=x)=_nC_x\cdot p^x\cdot (1-p)^{(n-x)}$