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Viktor [21]
3 years ago
9

determine the proceeds of a 10year promissory note discounted after after 4 years at 6% compounded quarterly with a maturity val

ue of $6000​
Mathematics
1 answer:
kenny6666 [7]3 years ago
5 0

Answer:

The Proceeds of maturity after 10 years is $1613.4

Step-by-step explanation:

Given as :

The maturity value = $ 6000

The rate applied at 6 % compounded quarterly

The Time period = 4 years

Now,

Amount = Principal × (1+\dfrac{\textrm Rate}{4\times 100})^{\textrm 4\times Time}

Or, Amount = 6000  × (1+\dfrac{\textrm 6}{4\times 100})^{\textrm 4\times 4}

Or, Amount = 6000 × (1.015)^{16}

Or,  Amount = 6000 × 1.2689

∴  Amount = $ 7613.4

So, The proceeds after 10 years = $ 7613.4 - $ 6000 = $ 1613.4

Hence The Proceeds of maturity after 10 years is $1613.4   Answer

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Vitek1552 [10]

Answer:

t=1.020s

Step-by-step explanation:

Given Equation:

5t-0.5at^{2} =0

Actually the given equation is the 2nd equation of motion

i.e. S =V_{i} t+0.5at^{2}

where S=0 because the astronaut jumps on the earth

and initial velocity V_{i}=5

to find time t, put the given value of a=9.8m/s^{2} in the given equation, we get

5t-0.5(9.8)t^{2} =0\\t(5-4.9t)=0\\ \ dividing\ both\ sides\ by\ t\ we \ get\\ 5-4.9t=0\\4.9t=5\\t=\frac{5}{4.9}\\ t=1.020s

it will take t=1.020s to reach the ground if he jumps on the Earth

3 0
3 years ago
What function is the inverse of the exponential function y = (1.5)x?
vagabundo [1.1K]

Correct question is;

What function is the inverse of the exponential function y = 1.5^(x)?

Answer:

y = log_1.5_x

Step-by-step explanation:

The inverse of exponential functions is usually written in form of logarithm.

For example inverse of y = p^(x) will be written as; y = log_p_(x)

Similarly applying this same pattern to our exponential function y = 1.5^(x), we have the inverse as;

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2 years ago
Find the circumference of the circle to the nearest 10th use 3.14 the radius is 25
Mashutka [201]

If the radius is 25, the diameter is 50.


Use C = (3.14)(50)


C = 157


No need round off to the nearest tenth.


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3 years ago
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