12 yo 5 yd what is the length of the hypotenuse
1 answer:
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Laura's age is 9 years.
Solution:
Let x be the age of April.
Laura's age = 2 years more than half of April's age
<u>Convert statement into algebraic expression:</u>
Half of April's age =
2 years more than half of April's age =
Combined age of April and Laura = 23
⇒ April's age + Laura's age = 23
To add the fractions make the denominators same.
Multiplying 2 on both numerator and denominator of unlike terms, we get
Denominators are same, now add the fractions.
Do cross multiplication.
Aprils's age = 14 years
Laura's age =
= 7 + 2
Laura's age = 9
Hence Laura's age is 9 years.