One way is to factor and group and get every 3
729=3 times 3 times 3 times 3 times 3 times 3
so we group the ones that happen 3 times
729=(3*3*3) times (3*3*3)
we know that we can take the cube root of each group and multiply the result
729=
![( \sqrt[3]{3*3*3})( \sqrt[3]{3*3*3})](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B3%5D%7B3%2A3%2A3%7D%29%28%20%5Csqrt%5B3%5D%7B3%2A3%2A3%7D%29)
=(3)(3)=9
the answer is 9
Fermat's little theorem states that

≡a mod p
If we divide both sides by a, then

≡1 mod p
=>

≡1 mod 17

≡1 mod 17
Rewrite

mod 17 as

mod 17
and apply Fermat's little theorem

mod 17
=>

mod 17
So we conclude that

≡1 mod 17
Answer:
46
Step-by-step explanation:
The geometry can be modeled by a right triangle. The diagonal measure is the hypotenuse, and the height is one leg. The width is the other leg, and can be found using the Pythagorean theorem.
__
<h3>Pythagorean theorem</h3>
The relation between the leg lengths (a, b) and the hypotenuse (c) is ...
c² = a² +b²
Solving for b gives ...
b = √(c² -a²)
<h3>application</h3>
In this problem, we have c=55 and a=30. Then the width of the TV is ...
b = √(55² -30²) = √(3025 -900) = √2125
b ≈ 46.098
The width of the TV is about 46.
Assuming the fish pond is round, what you're given is the circumference.
So you know that 2<span>πr = 27.
We want to solve for the diameter, or d = 2r. We should isolate that.
2r = 27/</span><span>π
2r = 8.59 yards, or ~9 yards.</span>