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4 years ago

What is 5/6 - (-3/4)

2 answers:

6 0

20/24-(-18/24)=38/24
Subtracting a negative is adding a positive.
20/24+18/38
38/24
24 goes into 38 once and 14/24 is left over.
1 14/24
Divide the fraction by two for simplest form.
1 7/12

Lesechka [4]4 years ago

3 0

5/6=20/24
-3/4=-18/24
20/24-(-18/24)=38/24
38/24=1 7/12

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Convert 0.875 inch to a fraction in simplest form. Click to select the correct answer.

inna [77]

This isnt the simplist but 875/1000 . Thats 875 over 1000.

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3 years ago

Mr. Loh is bored over winter break so he gets a temporary job at a halal cart. He gets paid 3$ for each chicken over rice that h

Masja [62]

Answer:

halal cart. Imao. does he sell fatoush

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10

zvonat [6]

The approximate difference in the ages of the two cars, which depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

$FV=P\left(1-\dfrac{r}{100}\right)^n$

Here, (P) is the price of the product, (r) is the rate of annual depreciation and (n) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is $n_1$ . Thus, by the above formula for the first car,

$0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}$

Take log both the sides as,

$\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85$

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is $n_2$ . Thus, by the above formula for the second car,

$0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}$

Take log both the sides as,

$\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14$

The difference in the ages of the two cars is,

$d=4.85-3.14\\d=1.71\rm years$

Thus, the approximate difference in the ages of the two cars, which depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0

2 years ago

Does anyone know how to do this?

BlackZzzverrR [31]

Answer:

the 8 means there will be 8 zeros after it so

62.00000000

3 0

3 years ago

The price of the box of 15 stickers is $6. The price of the box of 25 stickers is $8. All prices are without tax, and the price

spayn [35]

Answer:

A box of 50 stickers would cost $13

Explanation:

1- getting the equation representing the price:

We have two variables; the number of stickers and the price of the box

We can note that the price is the dependent variable (y) while the number of stickers is the independent one (x)

We are given that:

A box of 15 stickers cost $6..........> first point is (15,6)

A box of 25 stickers cost $8 ........> second point is (25,8)

The general equation of the linear line is:

y = mx + c

where m is the slope and c is the y-intercept

i. getting the slope:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{8-6}{25-15}=0.2$

The equation now became: y = 0.2x + c

ii. getting the y-intercept:

To get the y-intercept, use any of the given points and substitute in the equation we got in part i. I will use the point (15,6)

y = 0.2x + c

6 = 0.2(15) + c

c = 6 - 0.2(15) = 3

The final equation is:

y = 0.2x + 3

where y is the price of the box and x is the number of stickers it contains

2- getting the price of a box with 50 stickers:

To get the price of a box of 50 stickers, simply substitute with x = 50 in the equation we got from part 1

This is done as follows:

y = 0.2(50) + 3 = 13

Therefore, a box of 50 stickers will cost $13

Hope this helps :)

5 0

4 years ago