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alina1380 [7]
2 years ago
10

Which equation represents a parabola that has a focus of (0 0) and a directrix of y = 2

Mathematics
1 answer:
mel-nik [20]2 years ago
7 0

ANSWER

x ^{2}  =  - 4(y - 1).

EXPLANATION

Since the parabola has the (0, 0) and the directrix at y=2.

The equation is of the form

{(x - h)}^{2}  =  - 4p(y - k)

where (h,k) is the vertex.

The vertex is half way between the directrix and the focus.

The vertex will be at (0,1)

and is the distance from the vertex to the focus which is 1.

{(x - 0)}^{2}  =  - 4(1)(y - 1)

x ^{2}  =  - 4(y - 1)

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If the rate of change of the graph of a linear equation is 4 and the y-intercept is (0, 8), what is the linear equation that rep
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Algebra 2A Help !<br><br> Tadakimasu ~
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Function is p(x)=(x-4)^5(x^2-16)(x^2-5x+4)(x^3-64)

first factor into (x-r1)(x-r2)... form

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group the like ones
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)

multiplicity is how many times the root repeats in the function
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so

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baseically

(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the  root 1 and has multiplity 1

7 0
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