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alina1380 [7]
2 years ago
10

Which equation represents a parabola that has a focus of (0 0) and a directrix of y = 2

Mathematics
1 answer:
mel-nik [20]2 years ago
7 0

ANSWER

x ^{2}  =  - 4(y - 1).

EXPLANATION

Since the parabola has the (0, 0) and the directrix at y=2.

The equation is of the form

{(x - h)}^{2}  =  - 4p(y - k)

where (h,k) is the vertex.

The vertex is half way between the directrix and the focus.

The vertex will be at (0,1)

and is the distance from the vertex to the focus which is 1.

{(x - 0)}^{2}  =  - 4(1)(y - 1)

x ^{2}  =  - 4(y - 1)

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Answer:

You add it in your mind.

Step-by-step explanation:


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3 years ago
If 2a+b=6 and a−6=b, what is the value of a?
earnstyle [38]

Step-by-step explanation:

Given

2a + b = 6......equation 1

a - 6 = b

a = b + 6........equation 2

Putting equation 2 in equation 1

2 ( b + 6 ) + b = 6

2b + 12 + b = 6

3b = 6 - 12

3b = - 6

b = - 6 / 3

Therefore b = - 2

Now

a = - 2 + 6 = 4

hope it will help :)

3 0
3 years ago
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Please help me on this one i need it
sergiy2304 [10]
Sophia is more correct in her solution.

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3 years ago
Simplify the expression shown. You must show your work to receive credit.
ZanzabumX [31]

ANSWER

12 \sqrt{5}

EXPLANATION

The given expression is

\sqrt{2}  \times  \sqrt{72}  \times  \sqrt{5}

The middle radical contains a perfect square.

\sqrt{2}  \times  \sqrt{36 \times 2}  \times  \sqrt{5}

\sqrt{2}  \times  \sqrt{36}   \times  \sqrt{2} \times  \sqrt{5}

6\sqrt{2}  \times  \sqrt{2} \times  \sqrt{5}

Note that:

\sqrt{a}  \times  \sqrt{a}  = a

6\times 2 \sqrt{5}  = 12 \sqrt{5}

4 0
2 years ago
Z−4/9−1/3=5/9 Enter your answer as a fraction in simplest form in the box. z =
aleksklad [387]

Answer:

z = 4/3 or 1 1/3

Step-by-step explanation:

z−4/9−1/3=5/9

Change 1/3 to have a denominator of 9

1/3 *3/3 = 3/9

z−4/9−3/9=5/9

Combine like terms

z -7/9 = 5/9

Add 7/9 to each side

z-7/9+7/9 = 5/9+7/9

z = 12/9

z=4/3

or as a mixed number

z = 1 1/3

7 0
2 years ago
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