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melamori03 [73]
1 year ago
7

There are 26 prize tickets in a bowl, labeled A to Z. What is the probability that a prize ticket with a vowel will be chosen, n

ot replaced, and then another prize ticket with a vowel will be chosen? Does this represent an independent or dependent event? Explain.
Mathematics
1 answer:
AfilCa [17]1 year ago
7 0

The probability that a prize ticket with a vowel will be chosen, not replaced, and then another prize ticket with a vowel will be chosen is 0.031 or 3.1%. The events are dependent events.

Given that there are five vowels, which come from the letters A, E, I, O, and U, the likelihood of drawing a vowel is:

5/26

since there are a total of 26 alternatives available. After choosing that, we are left with 25 alternatives, 4 of which are vowels, thus the probability is:

4/25

The final likelihood is thus:

5/26 * (4/25) = 0.031

In other words, the likelihood is 3.1% when choosing a vowel and then another (without replacement).

The first event has an impact on the second event since there are fewer vowels and overall possibilities, hence the events are dependent.

Learn more about probability here :

brainly.com/question/16812448

#SPJ1

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In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. And the critical value would be given by:

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