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igomit [66]
3 years ago
8

20 POINTSSSSSSSSSSS AND BRAINLIESTTTTTTTTTTTTTSSSSSSSSSSSSSS

Mathematics
2 answers:
Setler79 [48]3 years ago
5 0
The answer is C!

2.5, move the decimal four places to the left. You are left with .00025
Assoli18 [71]3 years ago
5 0

Answer:

C

Step-by-step explanation:

Since the exponent on the 10 is negative, we need to move the decimal point to the left instead of the right. After moving the decimal point on the 2.5 to the left 4 places, we see that the answer is 0.00025.

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Leon drove 100 miles in 2 hours. Find the constant of variation.
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To find the constant variation, solve for only one hour (in this case).

Divide 100 with 2

100/2 = 50/1

Each hour is 50 miles driven, so your constant variation is 50 mph

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3 years ago
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Step-by-step explanation:

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The chosen topic is not meant for use with this type of problem.

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3 years ago
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Diano4ka-milaya [45]
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3 years ago
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Suppose the average tread-life of a certain brand of tire is 42,000 miles and that this mileage follows the exponential probabil
Ahat [919]

Answer: The probability that a randomly selected tire will have a tread-life of less than 65,000 miles is 0.7872 .

Step-by-step explanation:

The cumulative distribution function for exponential distribution is :-

P(X\leq x)=1-e^{\frac{-x}{\lambda}}, where \lambda is the mean of the distribution.

As per given , we have

Average tread-life of a certain brand of tire :  \lambda=\text{42,000 miles }

Now , the probability that a randomly selected tire will have a tread-life of less than 65,000 miles will be :

P(X\leq 65000)=1-e^{\frac{-65000}{42000}}\\\\=1-e^{-1.54761}\\\\=1-0.212755853158\\\\=0.787244146842\approx0.7872

Hence , the probability that a randomly selected tire will have a tread-life of less than 65,000 miles is 0.7872 .

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3 years ago
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