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ivolga24 [154]
3 years ago
7

The scatter plot shows the average heights of children up to age 5.

Mathematics
1 answer:
Over [174]3 years ago
7 0

Answer:

(a) y = 4.5x  + 22 -- The equation

(b) 31 inches

Step-by-step explanation:

Given

See attachment

Solving (a): The equation of the trend line.

We start  by calculating the slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

Where

(x_1,y_1) = (0,22)

(x_2,y_2) = (4,40)

So, we have:

m = \frac{40 - 22}{4 - 0}

m = \frac{18}{4}

m = 4.5

The equation is then calculated using:

y = m(x-x_1)+y_1

Where:

(x_1,y_1) = (0,22)

m = 4.5

y = 4.5(x - 0) + 22

Open bracket

y = 4.5x - 0 + 22

y = 4.5x  + 22

(b) The height of a 2 year old.

To do this, we substitute 2 for x in y = 4.5x  + 22

y = 4.5 * 2 + 22

y = 9+ 22

y = 31

The prediction is 31 inches

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today only, a sofa is being sold at a 36% discount. The sale price is $560. what was the price yesterday?
pashok25 [27]

Answer:

Step-by-step explanation:

Let yesterday's price  be x

Discount percentage = 36%

Sale price = $ 560

(100-36)% of x = 560

64 % *x = 560

\frac{64}{100}*x=560\\\\x=560*\frac{100}{64}\\\\x=875

Yesterday's price = $ 875

8 0
3 years ago
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Delvig [45]

Answer:

X = 6°

Step-by-step explanation:

In a set of parallel lines, the opposite angles and corresponding angles are similar. Since the opposite angle of 110° is the corresponding angle of 19x - 4, you can conclude that 19x - 4 = 110° ⇒ 19x = 114° ⇒ x = 6°.

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3 years ago
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8 0
3 years ago
Read 2 more answers
A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of
lina2011 [118]

Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean     x = 31,5

Sample standard deviation   s₂  = 8,35

Sample size        n₂ = 11

Ti-84 Calculator

Sample mean     y = 46,2

Sample standard deviation   s₁  = 9,99

Sample size        n₁ = 12

t(s)  = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s)  = 12,9 / √(99,8/12) + (69,72/11)

t(s)  = 12,9 / √8,32 + 6,34

t(s)  = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis               H₀      y - x > 1,80

Altenative Hypothesis       Hₐ      y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c)   critical value for

t(c) α; n₁ +n₂-2            df = 12 +11 -2     df  = 21

If we choose  CI = 95 %    then  α = 5 %   α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

8 0
3 years ago
Just do number 12 please
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Please make it clear:)
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