Question

Someone please help me with number 16

Answer 1

Answer:
Area of wall = $94 \frac{47}{48}$ ft

Explanation:
First, we know that:
1 in = 1/12 ft
Therefore, the dimensions of the wall would be as follows:
H = 7 ft 10 in = $7 \frac{10}{12}$ ft
B1 = 10 ft 2 in = $10 \frac{2}{12}$ ft
B2 = 14 ft 1 in = $14 \frac{1}{12}$ ft

For the trapezium, area can be calculated using the following the following formula:
Area of trapezium = Average base * height = $\frac{B1 + B2}{2}$ * height

Substitute with the given to get the area as follows:
Area of wall = ([$10 \frac{2}{12}$ + $14 \frac{1}{12}$] / 2) * $7 \frac{10}{12}$
Area of wall = $94 \frac{47}{48}$ ft

Hope this helps :)