Someone please help me with number 16
1 answer:
Answer:
Area of wall =
ft
Explanation:
First, we know that:
1 in = 1/12 ft
Therefore, the dimensions of the wall would be as follows:
H = 7 ft 10 in =
ft
B1 = 10 ft 2 in =
ft
B2 = 14 ft 1 in =
ft
For the trapezium, area can be calculated using the following the following formula:
Area of trapezium = Average base * height =
* height
Substitute with the given to get the area as follows:
Area of wall = ([ + ] / 2) * 
Area of wall = ft
Hope this helps :)
Area of wall =
Explanation:
First, we know that:
1 in = 1/12 ft
Therefore, the dimensions of the wall would be as follows:
H = 7 ft 10 in =
B1 = 10 ft 2 in =
B2 = 14 ft 1 in =
For the trapezium, area can be calculated using the following the following formula:
Area of trapezium = Average base * height =
Substitute with the given to get the area as follows:
Area of wall = ([
Area of wall =
Hope this helps :)
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Answer:
see explanation
Step-by-step explanation:
Given
2x² + x - 1 = 2 ( subtract 2 from both sides )
2x² + x - 3 = 0
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 2 × - 3 = - 6 and sum = + 1
The factors are - 2 and + 3
Use these factors to split the x- term
2x² - 2x + 3x - 3 = 0 ( factor the first/second and third/fourth terms )
2x(x - 1) + 3(x - 1) = 0 ← factor out (x - 1) from each term
(x - 1)(2x + 3) = 0
Equate each factor to zero and solve for x
x - 1 = 0 ⇒ x = 1
2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = -