Solution along with work is included in attachment.
Round 4,368 to the nearest ten.
2 answers:
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Every value{0.01, 0.29, 85%} can represent the probability of an event occurring except option d that is 1.5.
Given to us,
a.)
b.) 0.29
c.) 85%
d.)
The probability help us to know about the probability of specific events occurring.
For a sure event, the probability is always 1,
while for an event that will never happen the probability is always 0.
Thus, probability(p), .
Now looking at the options,
a.) = 0.01
b.) 0.29
c.) 85% = 0.85
d.) = 1.5
Now comparing each option with .
Therefore, the only option which is not feasible is option d that is 1.5.
Hence, every value{0.01, 0.29, 85%} can represent the probability of an event occurring except option d that is 1.5.
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