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Vladimir79 [104]
3 years ago
13

PLZ HELP ASAP SIMMILAR AND CONGRUENT TRIANGLES

Mathematics
1 answer:
Dvinal [7]3 years ago
8 0
LA=3.5; AY=7
LW=?

LW=LA+AW
AW=?

Let's analyze triangles LAY and YAW
1) Triangle LAY
Angle LAY is 90°
Suppose Angle ALY is x
The angle LYA is the complement of x, for example y:
x+y=90°→y=90°-x

2) Triangle YAW
Angle AYW is the complement of angle LAY (y), then the angle AYW must be equal to x.
Angle YAW is 90°, because the angle LAY is 90°

The triangles LAY and YAW are similars, because they have to congruent angles:
Angle LAY = 90° = Angle YAW
Angle ALY = x = Angle AYW
Then the sides of triangles LAY and YAW must be proportionals:
AW/AY=AY/LA
Replacing the known values:
AW/7=7/3.5
AW/7=2
Solving for AW. Multiplying both sides of the equation by 7:
7(AW/7)=7(2)
AW=14

Now:
LW=LA+AW
LW=3.5+14
LW=17.5

Answer: LW=17.5 units

  
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X²/9 + y²/16 = 1

The general for mula of an ellipse is:

(x-h)²/a²  + (y-k)²/b² = 1. Since h = k = 0, this ellipse
x²/9 + y²/16 = 1
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Moreover sin b>a  so the majore axis is (on the y-axis) and a the minor axis (on the x-axis) [Its shape is as a vertical egg].

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15 inches of snow fell in 12 hours. At this rate, how many inches of snow will fall in 3 days.
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a math teacher claims that she has developed a review course that increases the score of students on the math portion of a colle
madam [21]

Answer:

A.

H_0: \mu\leq514\\\\H_1: \mu>514

B. Z=2.255. P=0.01207.

C. Although it is not big difference, it is an improvement that has evidence. The scores are expected to be higher in average than without the review course.

D. P(z>0.94)=0.1736

Step-by-step explanation:

<em>A. state the null and alternative hypotheses.</em>

The null hypothesis states that the review course has no effect, so the scores are still the same. The alternative hypothesis states that the review course increase the score.

H_0: \mu\leq514\\\\H_1: \mu>514

B. test the hypothesis at the a=.10 level of confidence. is a mean math score of 520 significantly higher than 514? find the test statistic, find P-value. is the sample statistic significantly higher?

The test statistic Z can be calculated as

Z=\frac{M-\mu}{s/\sqrt{N}} =\frac{520-514}{119/\sqrt{2000}}=\frac{6}{2.661}=2.255

The P-value of z=2.255 is P=0.01207.

The P-value is smaller than the significance level, so the effect is significant. The null hypothesis is rejected.

Then we can conclude that the score of 520 is significantly higher than 514, in this case, specially because the big sample size.

C.​ do you think that a mean math score of 520 vs 514 will affect the decision of a school admissions adminstrator? in other words does the increase in the score have any practical significance?

Although it is not big difference, it is an improvement that has evidence. The scores are expected to be higher in average than without the review course.

D. test the hypothesis at the a=.10 level of confidence with n=350 students. assume that the sample mean is still 520 and the sample standard deviation is still 119. is a sample mean of 520 significantly more than 514? find test statistic, find p value, is the sample mean statisically significantly higher? what do you conclude about the impact of large samples on the p-value?

In this case, the z-value is

Z=\frac{520-514}{s/\sqrt{n}} =\frac{6}{119/\sqrt{350}} =\frac{6}{6.36} =0.94\\\\P(z>0.94)=0.1736>\alpha

In this case, the P-value is greater than the significance level, so there is no evidence that the review course is increasing the scores.

The sample size gives robustness to the results of the sample. A large sample is more representative of the population than a smaller sample. A little difference, as 520 from 514, but in a big sample leads to a more strong evidence of a change in the mean score.

Large samples give more extreme values of z, so P-values that are smaller and therefore tend to be smaller than the significance level.

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mr_godi [17]

Answer:

20%

Step-by-step explanation:

So, I would set this up as a proportion-

72          x

90        100

Cross multiply-

100 x 72 = 7200

Divide-

7200/90 = 80

Subtract-

100 - 80 = 20

So, it is a 20% decrease

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