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Vladimir79 [104]

2 years ago

13

PLZ HELP ASAP SIMMILAR AND CONGRUENT TRIANGLES

1 answer:

Dvinal [7]2 years ago

8 0

LA=3.5; AY=7
LW=?

LW=LA+AW
AW=?

Let's analyze triangles LAY and YAW
1) Triangle LAY
Angle LAY is 90°
Suppose Angle ALY is x
The angle LYA is the complement of x, for example y:
x+y=90°→y=90°-x

2) Triangle YAW
Angle AYW is the complement of angle LAY (y), then the angle AYW must be equal to x.
Angle YAW is 90°, because the angle LAY is 90°

The triangles LAY and YAW are similars, because they have to congruent angles:
Angle LAY = 90° = Angle YAW
Angle ALY = x = Angle AYW
Then the sides of triangles LAY and YAW must be proportionals:
AW/AY=AY/LA
Replacing the known values:
AW/7=7/3.5
AW/7=2
Solving for AW. Multiplying both sides of the equation by 7:
7(AW/7)=7(2)
AW=14

Now:
LW=LA+AW
LW=3.5+14
LW=17.5

Answer: LW=17.5 units

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Bond [772]

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6 0

2 years ago

find the standard form of equation of a line perpendicular to 4X plus 5Y equals 40 that includes the point -10, -3

snow_tiger [21]

The equation of line in standard form is 5x - 4y = -38

<em><u>Solution:</u></em>

Given that we have to find the equation of line perpendicular to 4x + 5y = 40 that includes the point (-10, -3)

<em><u>The equation of line in slope intercept form is given as:</u></em>

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given equation of line is:

4x + 5y = 40

Rearranging to slope intercept form, we get

5y = -4x + 40

$y = \frac{-4}{5}x + \frac{40}{5}\\\\y = \frac{-4}{5}x + 8$

On comparing the above equation with eqn 1,

$m = \frac{-4}{5}$

We know that product of slope of line and slope of line perpendicular to given line is equal to -1

Therefore,

$\frac{-4}{5} \times \text{ slope of line perpendicular to it } = -1\\\\\text{ slope of line perpendicular to it } = \frac{5}{4}$

Now find the equation of line with slope 5/4 and passing through (-10, -3)

Substitute $m = \frac{5}{4}$ and (x, y) = (-10, -3) in eqn 1

$-3 = \frac{5}{4}(-10) + c\\\\-3 = \frac{-25}{2} + c\\\\c = -3 + \frac{25}{2}\\\\c = \frac{-6 + 25}{2}\\\\c = \frac{19}{2}$

Substitute $c = \frac{19}{2}$ and $m = \frac{5}{4}$ in eqn 1

$y = \frac{5}{4}x + \frac{19}{2}$

The standard form of an equation is Ax + By = C

Therefore,

$\frac{5}{4}x - y = -\frac{19}{2}\\\\\frac{5x - 4y}{4} = \frac{-19}{2}\\\\5x - 4y = -38$

Thus the equation of line in standard form is found

4 0

2 years ago

Find the percent of the number. 30% of 90 is =

Vedmedyk [2.9K]

Answer:

27

Step-by-step explanation:

30% of 90 is 27

30/100 = ?/90

by cross multiplying, we can see that 30 times 90 is equal to 2700.

2700/100 = 27

? = 27

PLEASE GIVE BRAINLIEST!

Hope this helps :)

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2 years ago

What is: 9+8*2-9+30*1100/2

umka21 [38]

Answer:

16516

Step-by-step explanation:

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3 years ago

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Rút gọn các biểu thức sau:

siniylev [52]

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2 years ago